Indexing for cell arrays
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Joseph Lee
el 20 de Nov. de 2017
Comentada: Joseph Lee
el 22 de Nov. de 2017
I have 10x1300 cell array z, how do i find a certain value of z using indexing
find(abs(z-z_position)<intvl) did not work
and how do i do the opposite as well? eg. z{1,1}(1)
A portion of z, z value is random for each cell.
Columns 1296 through 1300
[1×23 double] [1×23 double] [1×29 double] [1×23 double] [1×25 double]
[1×27 double] [1×25 double] [1×25 double] [1×25 double] [1×27 double]
[1×21 double] [1×25 double] [1×27 double] [1×27 double] [1×25 double]
[1×27 double] [1×29 double] [1×29 double] [1×25 double] [1×23 double]
[1×27 double] [1×25 double] [1×23 double] [1×27 double] [1×27 double]
[1×27 double] [1×27 double] [1×23 double] [1×21 double] [1×23 double]
[1×25 double] [1×29 double] [1×27 double] [1×27 double] [1×27 double]
[1×27 double] [1×21 double] [1×21 double] [1×29 double] [1×27 double]
[1×25 double] [1×25 double] [1×25 double] [1×21 double] [1×27 double]
[1×23 double] [1×25 double] [1×25 double] [1×25 double] [1×23 double]
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Respuesta aceptada
Walter Roberson
el 20 de Nov. de 2017
cellfun( @(Z) find(abs(Z-z_position)<intvl), z, 'uniform', 0)
the output will be a cell array each element of which is the list of indices for the corresponding cell in z.
9 comentarios
Walter Roberson
el 21 de Nov. de 2017
Do you need to know just the value out of all of the M, or do you need to know which cell of M it came from and the index inside that cell?
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