converting a cell array of doubles in a matrix
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Haneya Qureshi
el 19 de Jun. de 2018
Comentada: OCDER
el 19 de Jun. de 2018
I have a variable A which looks like this:
1×2 cell array
{1×9 double} {1×9 double}
I want to convert it to a matrix, i.e, the first row of matrix should be what's inside the A{1} and second row of matrix should be what's inside A{2}. A is a cell, but A{1} and A{2} are doubles. How can i do this?
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Ameer Hamza
el 19 de Jun. de 2018
A{1} = rand(1,9);
A{2} = rand(1,9);
cell2mat(A')
A =
1×2 cell array
{1×9 double} {1×9 double}
ans =
Columns 1 through 7
0.0844 0.3998 0.2599 0.8001 0.4314 0.9106 0.1818
0.1361 0.8693 0.5797 0.5499 0.1450 0.8530 0.6221
Columns 8 through 9
0.2638 0.1455
0.3510 0.5132
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OCDER
el 19 de Jun. de 2018
A = {rand(1,10000), rand(1,10000)};
B = vertcat(A{:});
1 comentario
OCDER
el 19 de Jun. de 2018
cell2mat is certainly the right function for converting cell arrays to matrices while preserving the MxN dimension of the cell array. However, vertcat is a built-in function (meaning super optimized) and will run ~2x faster for your case.
A = {rand(1,10000), rand(1,10000)};
t1 = timeit(@() vertcat(A{:}), 1);
t2 = timeit(@() cell2mat(A), 1);
fprintf('cell2mat(A'') time is %0.2f times slower than vertcat(A{:})\n', t2/t1);
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