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I have 468 by 1 matrix of floating data. I need to convert it to binary with same dimensions, e.g., 468 by 1. Kindly help
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Sajid Sarwar
el 7 de Nov. de 2018
Cerrada: MATLAB Answer Bot
el 20 de Ag. de 2021
-1.9836
-0.0287
-0.4330
0.7517
-0.4883
-0.1712
0.2263
0.7347
.... 400+ rows here
-0.5308
-0.5600
-0.5302
-0.3920
-0.0819
-0.3893
-0.6267
0.0062
-0.2508
0.8580
0.2292
0.0196
-1.3797
-0.6845
-0.2160
convert it binary with same matrix dimensions
3 comentarios
Guillaume
el 7 de Nov. de 2018
Yes, I think it's a case of the OP not knowing what binary is. However, considering the complaint that Kalyan's answer generates an 8 column matrix, it does look like the OP is after a column vector of 0 and 1.
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KALYAN ACHARJYA
el 7 de Nov. de 2018
Editada: KALYAN ACHARJYA
el 7 de Nov. de 2018
Hope this is helpful, for example
a=[-1.23;-2.54;-1.50]
a =
-1.2300
-2.5400
-1.5000
>> d=dec2bin(typecast(int8(a),'uint8'))
d =
11111111
11111101
11111110
7 comentarios
James Tursa
el 7 de Nov. de 2018
Editada: James Tursa
el 7 de Nov. de 2018
You need to give us an explicit example of what you mean by a "double binary" type. Technically, MATLAB stores the double value in floating point binary already, so what is it that you actually want? E.g., if the double value is 1.5 then what would be your desired output?
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