Beginner question about for loops and indexing
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Callum Taylor
el 20 de Nov. de 2018
Comentada: Callum Taylor
el 21 de Nov. de 2018
I want to perform a function on each number in a series 'a' depending on whether it's odd or even. Then output this series of numbers 'b' as an array.
I don't know what to do next. So far my script doesn't output anything.
a = 1:5:150; % array before function applied
b = zeros(1,30); % used to store numbers from a after functions
counter = 0;
for series = [1:30]
r = rem(a,2); % r = 0 if number is even, r = 1 if number is odd
counter = counter + 1;
if r == 0
b = a(counter)*4 % if number in b is even, multiply it by 4
elseif r == 1
b = a(counter)^3 % if number in a is odd, cube it
end
end
I am an absolute beginner, really have no idea what I'm doing, please help?
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Brian Hart
el 20 de Nov. de 2018
Hi Callum,
You're really close.
First, you can move the "r = ... " line outside the loop to do the operation on the whole array at once.
Then inside the loop, you need to index the other variables the same way you did with "a(counter)".
So it looks like this:
a = 1:5:150; % array before function applied
b = zeros(1,30); % used to store numbers from a after functions
counter = 0;
r = rem(a,2); % r = 0 if number is even, r = 1 if number is odd
for series = [1:30]
counter = counter + 1;
if r(counter) == 0
b(counter) = a(counter)*4; % if number in b is even, multiply it by 4
elseif r(counter) == 1
b(counter) = a(counter)^3; % if number in a is odd, cube it
end
end
2 comentarios
Brian Hart
el 21 de Nov. de 2018
To encourage you to learn more about MATLAB, here's a different solution that does the same thing with few lines of code...
a = 1:5:150; % array before function applied
b = zeros(1,length(a)); % used to store result
b(rem(a,2)==0) = a(rem(a,2)==0) * 4; % Using logical indexing and vectorization
b(rem(a,2)==1)=a(rem(a,2)==1).^3;
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