taylor series expansion help
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
syms x
valuex=input('What is the value of x? ')
subs(taylor(exp(x),x, 'OrderMode','Relative','Order',valuex), valuex)
I need to modify my solution above so that, as well as computing and displaying the result of the Taylor series expansion, it also computes and displays the number of terms required for the approximation to be accurate to within 0.01.
The Taylor series for the exponential function e^x is 1 + (x^1)/1! + (x^2)/2! + (x^3)/3 ...
2 comentarios
Rik
el 25 de En. de 2019
This is probably easiest to solve by not using symbolic variables, but using an explicit loop instead.
Walter Roberson
el 25 de En. de 2019
? To confirm, the x that you evaluate the taylor series at, is to be the same as the Order (that is, the highest power to be used in the series) ??
Respuestas (0)
Ver también
Categorías
Más información sobre Calculus en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!