Borrar filtros
Borrar filtros

Determining length of values in cell

5 visualizaciones (últimos 30 días)
Katrina Anderson
Katrina Anderson el 5 de Feb. de 2019
Comentada: KSSV el 6 de Feb. de 2019
Hi,
I have a single column cell with numbers between 1 - 5 (each allocated to a behaviour). This is used to plot a line graph so I can see what behaviour occured at each given time period. My question: Is there a way to extract features such as for Step it occurs when the behaviour "4" is represented on the line graph for greater than 700 data points. Is there a way I can do that?
And also determine how many times in the cell the behaviour changes. Not sure if this makes sense. Ask me to clarify otherwise.
Thanks
Katrina
  2 comentarios
TADA
TADA el 5 de Feb. de 2019
can you share a small example to make it clearer?
Katrina Anderson
Katrina Anderson el 5 de Feb. de 2019
Editada: Katrina Anderson el 5 de Feb. de 2019
thankyou!
I will attach a screenshot of a small part of the graph:
possible_threshes = {'Standing', 'WS', 'PG', 'Step', 'LD'};
thresh_vals = [1, 2, 3, 4, 5]
[tf, idx] = ismember(testmodel2(:,1), possible_threshes);
Behaviourcoded(tf, 1) = num2cell( thresh_vals( idx(tf) ) );
and thats how I got to that.
As you can see in the graph. Around the 8 - that is one step not two. Because there is a very short segment of '4'.
Hope that makes more sense?
Thankyou!!

Iniciar sesión para comentar.

Respuesta aceptada

KSSV
KSSV el 5 de Feb. de 2019
Editada: KSSV el 5 de Feb. de 2019
If A is your data...you can use logicals like ==, >, < etc..to find the locations. For example, if you want where 4 is present. If the data is in cell, you need to use flower braces: A{1} ....
idx = find(A==4) ;
  2 comentarios
Katrina Anderson
Katrina Anderson el 6 de Feb. de 2019
so like this:
idx = find([Behaviourcoded{:}] == 4);
and how would I find the incidence of 4 appearing 700 data points or more consecutively. Is this possible?
Thankyou!
KSSV
KSSV el 6 de Feb. de 2019
YOu can use diff and check....

Iniciar sesión para comentar.

Más respuestas (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by