How to replace 2x2 zero sub matrices by different 2x2 matrices ?
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parag gupta
el 18 de Mzo. de 2019
Editada: parag gupta
el 18 de Mzo. de 2019
How to replace 2x2 zero submatrix of B with 2x2 matrices different matrice.I have 12 matrices of size 2x2 and want to replace zeros of B by those matrices.
B =
0.8776 0.6513 0 0 0 0 0 0
0.0144 0.8646 0 0 0 0 0 0
0 0 0.2943 0.0560 0 0 0 0
0 0 0.1799 0.8169 0 0 0 0
0 0 0 0 0.9263 0.5289 0 0
0 0 0 0 0.0682 0.6944 0 0
0 0 0 0 0 0 0.5811 0.2124
0 0 0 0 0 0 0.6372 0.5433
Thanks
8 comentarios
Guillaume
el 18 de Mzo. de 2019
The loop would imply that you want to create 12 matrices. However, since it overwrites the matrices in the previous step, you'll end up with only 3 matrices. The ones created on the last step of the loop.
While you say that you have 12 matrices, your I want solution in this form implies that there are only 3 matrices, which are rotated on each row.
A bit confusing as to what you have.
I doubt it will be difficult to do what you want, but the method will vary depending on exactly what it is that you want. So, please clarify.
Respuesta aceptada
Matt J
el 18 de Mzo. de 2019
Editada: Matt J
el 18 de Mzo. de 2019
basically i want solution in this form
x p1 p2 p3
p1 x p2 p3
p1 p2 x p3
p1 p2 p3 x
C={zeros(2), p1,p2,p3};
result=B+cell2mat( C(toeplitz(1:4)) );
3 comentarios
Matt J
el 18 de Mzo. de 2019
Very similar to things I've already mentioned:
B(B==0)=cat(3,matrix4,matrix7,matrix10,matrix1,matrix8,matrix11,...
matrix2,matrix5,matrix12,matrix3,matrix6,matrix9);
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