Counting values above a threshold within a matrix.
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Gareth Evans
el 17 de Sept. de 2012
Comentada: Emmagnio Desir
el 5 de Sept. de 2023
Hello,
Im looking at finding a way of counting values that are >0 from a matrix, for example:-
if true %if statement used to display matrix correctly
00100
01110
11111
01110
00100
end
Would provide the output 1,3,5,3,1. Any help would light up my day.
Cheers
Gareth
1 comentario
Azzi Abdelmalek
el 17 de Sept. de 2012
Editada: Azzi Abdelmalek
el 17 de Sept. de 2012
is this your matrix?
0 0 2 0 0
0 3 4 5 0
1 2 3 4 5
0 6 5 4 0
0 0 3 0 0
Respuesta aceptada
Greg
el 17 de Sept. de 2012
sum(myMat>0, 2)
the result is the number of values in each row > 0.
3 comentarios
Más respuestas (2)
Babak
el 17 de Sept. de 2012
you can run the below function for each of your numbers:
function num_of_1s = no1(n)
if n==0
num_of_1s = 0;
else
length = floor(log10(n))+1;
num_of_1s = 0;
for j=length:-1:1
if floor(log10(n)) == j-1
num_of_1s = num_of_1s +1;
n = n-10^(j-1);
end
end
end
end
Then say for example:
no1(1010111)
which returns
5
nah
el 17 de Sept. de 2012
A simple way is:
myMat =
0 0 2 0 0
0 3 4 5 0
1 2 3 4 5
0 6 5 4 0
0 0 3 0 0
[nrows,ncols] = size(myMat);
counts_above_0 = zeros(nrows,1);
for rx = 1:nrows
counts_above_0(rx,1) = length(find(myMat(rx,:)>0));
end
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