How to find an equation of the tangent line to the curve f(x,y) =0 at the....

the points (2.4, -2.7927) and (2.4, 2.7127)

f(x,y) = 4x + 2y -xy +3x^2 -5y^2 +5

[darova]

WHere is MATLAB? It's just Math

[Peter Pyrka]

my question is how I would do this problem in Matlab

[darova]

How would you do this on paper?

Answer 1

[Mani Teja]

Hello Peter,

This should help:

syms x y f(x,y)

f(x,y) = 4*x + 2*y -x*y +3*x^2 -5*y^2 +5;

a = f(2.4, -2.7927);

a = vpa(a,4); % Just to make it look better

b = f(2.4, 2.7127) ;

b = vpa(b,4);

Regards

Mani