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How to find longest sequennce within a character array?

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That Guy
That Guy el 16 de Nov. de 2020
Comentada: Image Analyst el 16 de Nov. de 2020
lets say Im given a random character array such as: 'aaabee' and i want to find the longest sequence of vowels. How would i go about doing this?
so far I have:
cArr = 'aaabee';
vow = ['a', 'e', 'i', 'o', 'u'];
ans = strfind(cArr, vow);
but this just returns: [ ]
anyhelp would be appreciated!

Respuestas (2)

Ameer Hamza
Ameer Hamza el 16 de Nov. de 2020
Editada: Ameer Hamza el 16 de Nov. de 2020
You can use regexp
cArr = 'xzyhd';
vow = '([aeiou]+)';
tkns = regexp(cArr, vow, 'tokens');
if isempty(tkns)
n = 0;
else
n = max(cellfun(@numel, [tkns{:}]));
end
Result
>> n
n =
5
  3 comentarios
That Guy
That Guy el 16 de Nov. de 2020
Editada: That Guy el 16 de Nov. de 2020
this works, i just need it to output zero when a string without vowels is entered such as 'xzyhd' or ' ' .
sorry im so helpless this is my first experince with coding:(
Ameer Hamza
Ameer Hamza el 16 de Nov. de 2020
I have updated the answer. Now it will output 0 for the mentioned cases.

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Setsuna Yuuki.
Setsuna Yuuki. el 16 de Nov. de 2020
Editada: Setsuna Yuuki. el 16 de Nov. de 2020
cArr = 'aaabee';
vow = ['a', 'e', 'i', 'o', 'u'];
for n=1:length(vow)
a = strfind(cArr, vow(n)); %search letter by letter
repeat{n} = a; %place in "cArr"
if (a ~= NaN)
long(n) = length(a); %number of repetitions
else
long(n) = 0;
end
end
t = table(vow',long')
Table:
  4 comentarios
Setsuna Yuuki.
Setsuna Yuuki. el 16 de Nov. de 2020
Editada: Setsuna Yuuki. el 16 de Nov. de 2020
has been interesting this problem, i changed all code because I understood bad your problem.
clear large;
cArr = 'aaeeaaapriioaeaaa';
vow = ['a', 'e', 'i', 'o', 'u'];
var = 1;
for n=1:length(vow)
a = strfind(cArr, vow(n));
if(var == 1)
var(length(var):(length(var)+length(a))-1)=a;
else
var(length(var)+1:length(var)+length(a))=a;
end
end
var = sort(var); m = 0;
cont = 1;
for n = 1:length(var)-1
if(var(n) == (var(n+1)-1) && n ~= length(var)-1)
cont = cont +1;
elseif (var(n) ~= (var(n+1)-1))
m = m+1;
large(m) = cont;
cont = 1;
elseif(n == (length(var)-1))
cont = cont+1;
m = m+1;
large(m) = cont;
end
end
[longSeq, index] = max(large);
fprintf("The longest sequence is %i and is the sequence %i \n",longSeq, index);
I think I did this in C ++ jaja xd
Image Analyst
Image Analyst el 16 de Nov. de 2020
What's the use case for this quirky thing? Why do you need to do it? It's not your homework you're asking people to do for you, is it? What's the real world use for this?

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