Vectors must be the same lengths; plotting
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I have googled this to death, the common error was people looping arrays. I just have 2 simple sets and cant see where the error is.
simulated=[0.0000000 4.3830000 4.9470000 2.0180000 0.1761000 0.0162800 4.3650000 4.9540000 2.0170000 0.1760000 0.0162700 ]
actual= [0.0750000 4.0750000 4.7630000 3.5130000 0.5125000 0.1375000 2.6380000 4.5750000 4.8880000 1.5130000 0.3250000 ]
x = 0:0.0002:0.01;
plot(x, simulated, x, actual);
legend('Simulated', 'Actual')
ylabel('Current (mA)')
xlabel('Time ( mS )')
title('Current across R2 as a function of VS','FontSize',12)
4 comentarios
waqas muhammad
el 16 de En. de 2018
can you please tell me how did you solve the problem of number of elements and how you made it equal?
Respuestas (1)
Smith
el 30 de Oct. de 2016
You just need to modify variable x to match the size of variable simulated or variable actual.
simulated=[0.0000000 4.3830000 4.9470000 2.0180000 0.1761000 0.0162800 4.3650000 4.9540000 2.0170000 0.1760000 0.0162700 ]
actual= [0.0750000 4.0750000 4.7630000 3.5130000 0.5125000 0.1375000 2.6380000 4.5750000 4.8880000 1.5130000 0.3250000 ]
x = linspace(0,0.01,length(actual));
plot(x, simulated, x, actual);
legend('Simulated', 'Actual')
ylabel('Current (mA)')
xlabel('Time ( mS )')
title('Current across R2 as a function of VS','FontSize',12)
3 comentarios
Jan
el 14 de Nov. de 2016
@assiya malik: Please do not post a new question as a comment to an answer, but open a new thread. Note that the problem is hidding inside "calculated by Runge Kutta 4 method" and not shown here. It does not matter how you define the variables before you redefine them by any computations.
Komal Kumawat
el 2 de Oct. de 2020
%*********************************************************% %Defining the frequency vector and the mass matrix, %damping matrix, the stiffness matrix and the amplitude of %the excitation force. %*********************************************************% f=linspace(0,0.7,50); m=[1 0;0 2]; k=[2 -1;-1 1]; c=[0.002 -0.001;-0.001 0.001]; fi=[1;1]; %*********************************************************% %Calculating the amplitude and the phase for each frequency %defined by the frequency vector. %*********************************************************% for i = 1:50 omega(i)=2*pi*f(i); %omega in terms of frequency omega2(i)=omega(i)*omega(i); % squaring omega a11=-omega2(i)*m+k; % representing the left hand… a12=omega(i)*c; % matrix of the single matrix… a21=-omega(i)*c; % equation a22=-omega2(i)*m+k; a=[a11 a12;a21 a22]; b=inv(a); c1=[0;0;fi]; d(1,i)=b(1,:)*c1; d(2,i)=b(2,:)*c1; d(3,i)=b(3,:)*c1; d(4,i)=b(4,:)*c1; x(1,i)=sqrt(abs(d(1,i))^2+abs(d(3,i))^2); x(2,i)=sqrt(abs(d(2,i))^2+abs(d(4,i))^2); p(1,i)=atan(d(1,i)/d(3,i))*180/pi; if p(1,i)<0 % to check whether the angle is negative or not. p(1,i)=180+p(1,i); else
p(1,i)=p(1,i);
end
p(2,i)=atan(d(2,i)/d(4,i))*180/pi;
if p(2,i)<0
if d(4,i)<0
p(2,i) = -180 + p(2,i)
else
p(2,i)=180+p(2,i);
end
else
p(2,i)=p(2,i);
end
end
figure(1)
plot(f,x(1,:));grid
xlabel(‘Frequency’)
ylabel(‘Amplitude of Mass 1’)
figure(2)
plot(f,x(2,:));grid
xlabel(‘Frequency’)
ylabel(‘Amplitude of Mass 2’)
figure(3)
plot(f,p(1,:));grid
xlabel(‘Frequency’)
ylabel(‘Phase of Mass 1’)
figure(4)
plot(f,p(2,:));grid
xlabel(‘Frequency’)
ylabel(‘Phase of Mass 2’)
Why this shows error, please tell me the solution, actually this is my project
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