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Using If for syms

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Hossein Alishahi
Hossein Alishahi el 6 de Mzo. de 2021
Comentada: Hossein Alishahi el 6 de Mzo. de 2021
Hi,
I hope you are keeping safe.
I have a urgent question in matlab. Could you please give me sime advice in this regard. I wrote following code where
"function F = fun(x,y,alpha1,alpha2,beta1,beta2,lambda)
F= log((1+alpha1*x./(1+alpha2*y))) -lambda*log((1+beta1*x./(1+beta2*y)));
end"
Main Code
Z=fun(x,P-x,alpha1,alpha2,beta1,beta2,lambda);
z=solve(Z==0);
for i=1:length(z)
z(i,1)=piecewise(z(i,1)<=0,0)
y(i)=P-z(i,1)
S(i)=fun(z(i,1),y(i),alpha1,alpha2,beta1,beta2,lambda)
end
I want to z(i,1)=0 if z(i,1)<=0 or complex and if z(i,1)>0, claculate S(i) but there is a problem with piecewise() which cannot be solved for me.
Could you please help me to write it. P, alpha1, alpha2, beta1, beta2, and lambda are desired positive valuse.
Many Thanks in advance.

Respuestas (1)

Walter Roberson
Walter Roberson el 6 de Mzo. de 2021
subs(piecewise(x<3,0),x,5)
ans = NaN
That is, if no condition is matched by the piecewise then the output is undefined, NaN. Not 0 or empty.
piecewise(imag(z(i))~=0 || z(i)<0, 0, S(i))
  6 comentarios
Walter Roberson
Walter Roberson el 6 de Mzo. de 2021
I will need the values for the constants to test with
Hossein Alishahi
Hossein Alishahi el 6 de Mzo. de 2021
Thank you for your consideration.
I give you two case which meet all states
1.P=3, alpha1=1, alpha2=0.2, beta1=1, beta2=2, and lambda=2.
2.P=3, alpha1=1, alpha2=2, beta1=3, beta2=4, and lambda=5
Thanks in advance

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