Save 360 arrays in a cell

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mikel lasa
mikel lasa el 15 de Abr. de 2021
Respondida: mikel lasa el 15 de Abr. de 2021
Hello,
My programs loads 360 images (laser stripe) and from each image gets the 0 crossing of all rows. My issue is that after processing all images, im not able to save the 0 crossing arrays into a cell so I can post process them. Here my code:
clc; clear all; close all;
%% CARGAR LAS IMAGENES (load images)
for k = 1:360
jpgFilename = sprintf('%d.jpg', k);
fullFileName = fullfile('C:\MASTER\S2\percepcion\laser360\imagenes', jpgFilename);
if exist(fullFileName, 'file')
imageData = imread(fullFileName );
imageData=imrotate(imageData,90);
% se binariza la imagen (binarization)
img_o=rgb2gray(imageData);
mask=(img_o(:,:) > 50);
imageData = bsxfun(@times, img_o, cast(mask, 'like', img_o));
% figure()
% imshow(imageData)
% title('Binarizada')
%
[rows, columns, numberOfColorChannels] = size(imageData);
img_peaks = NaN(rows, 1);
img_puntos = zeros(rows, columns);
Xp = [];
Yp = [];
Xn=[];
Yn=[];
m=[];
n=[];
zerocross=[];
coefficients=[];
lineaslaser=cell(k,1);
%se busca la linea del 0 crossing
for icross=1:rows
img_puntos(icross,:)=imageData(icross,:);
%filtrado
filtrado=sgolayfilt(double(img_puntos(icross,:)),3,33 );
for ks=1:length(filtrado)
if filtrado(ks)<0
filtrado(ks)=0;
end
end
%derivada (gradient)
derivada=gradient(filtrado);
%maximo y minimo
[Yp(icross),Xp(icross)]=max(derivada);
[Yn(icross),Xn(icross)]=min(derivada);
%coeficientes de la recta (line coefs)
m(icross)= (Yp(icross)-Yn(icross))/(Xp(icross)-Xn(icross));
n(icross)= (Yp(icross)-m(icross)*Xp(icross));
% 0 crossing
zerocross(icross)= -n(icross)/m(icross);
img_peaks(icross) = zerocross(icross);
end
axis=1:1920;
img_peaks((1:10),1)=NaN;
img_peaks((1500:1920),1)=NaN;
% save 360 lines in a cell
lineaslaser{k}=img_peaks(k);
% figure()
% plot(axis,img_peaks)
% title('plot perfil de la pieza (0 crossing)')
else
warningMessage = sprintf('Warning: image file does not exist:\n%s', fullFileName);
uiwait(warndlg(warningMessage));
end
end
  3 comentarios
mikel lasa
mikel lasa el 15 de Abr. de 2021
Yes, I want to save an entire vector in a cell for each loop. There is my problem, for each loop a vector is generated, so my aim is to create a variable that saves 360 vectors. I thought that cell is maybe the right way to do that.
Apart from that:
img_peaks((1:10),1)=NaN;
The first 10 elements are NaN because each image has some noise, I delete that noise this way. Its just, for cleaning.
DGM
DGM el 15 de Abr. de 2021
Okay. If you move the preallocation outside the main loop and set that line to
lineaslaser{k}=img_peaks;
does it help?

Iniciar sesión para comentar.

Respuesta aceptada

mikel lasa
mikel lasa el 15 de Abr. de 2021
Edit:
I have achieved what I was looking for. As you said I deleted this line:
lineaslaser=cell(k,1);
and I changed my this line:
lineaslaser{k}=img_peaks(k);
for this one:
lineaslaser{k}=img_peaks(:,1);
now works, I have a 360 element cell where each cell is a 1920x1 vector. Thanks for your help!

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