Average a cell with ignoring NaN

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Ahmad Bayhaqi
Ahmad Bayhaqi el 29 de Abr. de 2021
Comentada: Jan el 30 de Abr. de 2021
Hi all,
I want to average with ignoring the NaN. I used the script below:
Intens2 = cellfun(@(C) cellfun(@mean, C), new_table3.extData, 'uniform', 0)
and the and I do average to Intens2
Intens3=cellfun(@mean, Intens2);
Is there a way to average in Intens2 and Intens2 with ignoring NaN?
where I can put 'omitnan'?
Thank you very much,
  1 comentario
Jan
Jan el 29 de Abr. de 2021
Please post an example for your inputs.

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Jan
Jan el 29 de Abr. de 2021
C = {[1,2,4,6,NaN], [NaN, 2, 3, NaN]};
MC = cellfun(@(x) mean(x, 'omitnan'), C)
MC = 1×2
3.2500 2.5000
  2 comentarios
Ahmad Bayhaqi
Ahmad Bayhaqi el 29 de Abr. de 2021
Hi @Jan, yes it works.
Thank you very much
Jan
Jan el 30 de Abr. de 2021
You are welcome. There are 3 nested cellfun calls in your code. Usually loops are faster than the nice cellfun. I'd post a loop method, if it is clear, what exactly your inputs are.

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