Find count of repeated letters (sequence)
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Sir,
How to find the no. of repeated sequence (letters) in the given sentence.
for example, a="I want THAAAAAT APPPPPLE ):):): totally unprepared";
The No. of repeated sequences are: 3
ie.,
1. THAAAAAT
2. APPPPPLE
3. ):):):
thanks
4 comentarios
Walter Roberson
el 9 de Oct. de 2013
Your #3, ):):): does not have continuously repeated symbols.
If the repeated sequences are to be identified, then why would all of THAAAAAT be output, and not just AAAAA ?
Respuestas (2)
Cedric
el 8 de Oct. de 2013
Editada: Cedric
el 8 de Oct. de 2013
Try to understand the following and fine-tune it to your needs:
n = sum( diff([0, diff(a)==0]) == 1 )
In particular, evaluate
diff(a)==0
and see how your problem actually translates into counting clusters of the outcome of diff(a)==0.
4 comentarios
Cedric
el 10 de Oct. de 2013
Editada: Cedric
el 10 de Oct. de 2013
You seem to indicate that one repeated sequence is '):'. As far as I am concerned, there is no simple generic solution if you want to detect repeated, arbitrary patterns. To illustrate,
'AABBCCDDEEFFAABBCCDDEEFF'
Here, repeated patterns are
'AA', 'BB', .., 'FF', 'AABB', 'BBCC', .., 'AABBCC', 'BBCCDD', ..,
'AABBCCDD', 'BBCCDDEE', .., 'AABBCCDDEEFF'
Using regular expressions, we can probably get some solution but it will be prohibitively time consuming.
Sean de Wolski
el 10 de Oct. de 2013
Yeah, every emoticon would have to be predefined. For the chatroom we use here there are even word emoticons like (b) which inserts a frosty beer mug or (ply) which inserts an image of a playing card.
Walter Roberson
el 1 de Dic. de 2016
a='I want THAAAAAT APPPPPLE ):):): totally unprepared';
regexp(a, '(.+)\1{2,}', 'match')
ans =
1×3 cell array
'AAAAA' 'PPPPP' '):):):'
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