anova
Analysis of variance for linear regression model
Description
Examples
Create a component ANOVA table from a linear regression model of the hospital data set.
Load the hospital data set and create a model of blood pressure as a function of age and gender.
load hospital tbl = table(hospital.Age,hospital.Sex,hospital.BloodPressure(:,2), ... 'VariableNames',{'Age','Sex','BloodPressure'}); tbl.Sex = categorical(tbl.Sex); mdl = fitlm(tbl,'BloodPressure ~ Sex + Age^2')
mdl =
Linear regression model:
BloodPressure ~ 1 + Age + Sex + Age^2
Estimated Coefficients:
Estimate SE tStat pValue
_________ ________ ________ _________
(Intercept) 63.942 19.194 3.3314 0.0012275
Age 0.90673 1.0442 0.86837 0.38736
Sex_Male 3.0019 1.3765 2.1808 0.031643
Age^2 -0.011275 0.013853 -0.81389 0.41772
Number of observations: 100, Error degrees of freedom: 96
Root Mean Squared Error: 6.83
R-squared: 0.0577, Adjusted R-Squared: 0.0283
F-statistic vs. constant model: 1.96, p-value = 0.125
Create an ANOVA table of the model.
tbl = anova(mdl)
tbl=4×5 table
SumSq DF MeanSq F pValue
______ __ ______ _______ ________
Age 18.705 1 18.705 0.40055 0.52831
Sex 222.09 1 222.09 4.7558 0.031643
Age^2 30.934 1 30.934 0.66242 0.41772
Error 4483.1 96 46.699
The table displays the following columns for each term except the constant (intercept) term:
SumSq— Sum of squares explained by the term.DF— Degrees of freedom. In this example,DFis 1 for each term in the model and n – p for the error term, where n is the number of observations and p is the number of coefficients (including the intercept) in the model. For example, theDFfor the error term in this model is 100 – 4 = 96. If any variable in the model is a categorical variable, theDFfor that variable is the number of indicator variables created for its categories (number of categories – 1).MeanSq— Mean square, defined byMeanSq = SumSq/DF. For example, the mean square of the error term, mean squared error (MSE), is 4.4831e+03/96 = 46.6991.F— F-statistic value to test the null hypothesis that the corresponding coefficient is zero, computed byF = MeanSq/MSE, whereMSEis the mean squared error. When the null hypothesis is true, the F-statistic follows the F-distribution. The numerator degrees of freedom is theDFvalue for the corresponding term, and the denominator degrees of freedom is n – p. In this example, each F-statistic follows an -distribution.pValue— p-value of the F-statistic value. For example, the p-value forAgeis 0.5283, implying thatAgeis not significant at the 5% significance level given the other terms in the model.
Create a summary ANOVA table from a linear regression model of the hospital data set.
Load the hospital data set and create a model of blood pressure as a function of age and gender.
load hospital tbl = table(hospital.Age,hospital.Sex,hospital.BloodPressure(:,2), ... 'VariableNames',{'Age','Sex','BloodPressure'}); tbl.Sex = categorical(tbl.Sex); mdl = fitlm(tbl,'BloodPressure ~ Sex + Age^2')
mdl =
Linear regression model:
BloodPressure ~ 1 + Age + Sex + Age^2
Estimated Coefficients:
Estimate SE tStat pValue
_________ ________ ________ _________
(Intercept) 63.942 19.194 3.3314 0.0012275
Age 0.90673 1.0442 0.86837 0.38736
Sex_Male 3.0019 1.3765 2.1808 0.031643
Age^2 -0.011275 0.013853 -0.81389 0.41772
Number of observations: 100, Error degrees of freedom: 96
Root Mean Squared Error: 6.83
R-squared: 0.0577, Adjusted R-Squared: 0.0283
F-statistic vs. constant model: 1.96, p-value = 0.125
Create a summary ANOVA table of the model.
tbl = anova(mdl,'summary')tbl=7×5 table
SumSq DF MeanSq F pValue
______ __ ______ _______ ________
Total 4757.8 99 48.059
Model 274.73 3 91.577 1.961 0.12501
. Linear 243.8 2 121.9 2.6103 0.078726
. Nonlinear 30.934 1 30.934 0.66242 0.41772
Residual 4483.1 96 46.699
. Lack of fit 1483.1 39 38.028 0.72253 0.85732
. Pure error 3000 57 52.632
The table displays tests for groups of terms: Total, Model, and Residual.
Total— This row shows the total sum of squares (SumSq), degrees of freedom (DF), and the mean squared error (MeanSq). Note thatMeanSq = SumSq/DF.Model— This row includesSumSq,DF,MeanSq, F-statistic value (F), and p-value (pValue). Because this model includes a nonlinear term (Age^2),anovapartitions the sum of squares (SumSq) ofModelinto two parts:SumSqexplained by the linear terms (AgeandSex) andSumSqexplained by the nonlinear term (Age^2). The corresponding F-statistic values are for testing the significance of the linear terms and the nonlinear term as separate groups. The nonlinear group consists of theAge^2term only, so it has the same p-value as theAge^2term in the Component ANOVA Table.Residual— This row includesSumSq,DF,MeanSq,F, andpValue. Because the data set includes replications,anovapartitions the residualSumSqinto the part for the replications (Pure error) and the rest (Lack of fit). To test the lack of fit,anovacomputes the F-statistic value by comparing the model residuals to the model-free variance estimate computed on the replications. The F-statistic value shows no evidence of lack of fit.
Fit a linear regression model that contains a categorical predictor. Reorder the categories of the categorical predictor to control the reference level in the model. Then, use anova to test the significance of the categorical variable.
Model with Categorical Predictor
Load the carsmall data set and create a linear regression model of MPG as a function of Model_Year. To treat the numeric vector Model_Year as a categorical variable, identify the predictor using the 'CategoricalVars' name-value pair argument.
load carsmall mdl = fitlm(Model_Year,MPG,'CategoricalVars',1,'VarNames',{'Model_Year','MPG'})
mdl =
Linear regression model:
MPG ~ 1 + Model_Year
Estimated Coefficients:
Estimate SE tStat pValue
________ ______ ______ __________
(Intercept) 17.69 1.0328 17.127 3.2371e-30
Model_Year_76 3.8839 1.4059 2.7625 0.0069402
Model_Year_82 14.02 1.4369 9.7571 8.2164e-16
Number of observations: 94, Error degrees of freedom: 91
Root Mean Squared Error: 5.56
R-squared: 0.531, Adjusted R-Squared: 0.521
F-statistic vs. constant model: 51.6, p-value = 1.07e-15
The model formula in the display, MPG ~ 1 + Model_Year, corresponds to
,
where and are indicator variables whose value is one if the value of Model_Year is 76 and 82, respectively. The Model_Year variable includes three distinct values, which you can check by using the unique function.
unique(Model_Year)
ans = 3×1
70
76
82
fitlm chooses the smallest value in Model_Year as a reference level ('70') and creates two indicator variables and . The model includes only two indicator variables because the design matrix becomes rank deficient if the model includes three indicator variables (one for each level) and an intercept term.
Model with Full Indicator Variables
You can interpret the model formula of mdl as a model that has three indicator variables without an intercept term:
.
Alternatively, you can create a model that has three indicator variables without an intercept term by manually creating indicator variables and specifying the model formula.
temp_Year = dummyvar(categorical(Model_Year));
Model_Year_70 = temp_Year(:,1);
Model_Year_76 = temp_Year(:,2);
Model_Year_82 = temp_Year(:,3);
tbl = table(Model_Year_70,Model_Year_76,Model_Year_82,MPG);
mdl = fitlm(tbl,'MPG ~ Model_Year_70 + Model_Year_76 + Model_Year_82 - 1')mdl =
Linear regression model:
MPG ~ Model_Year_70 + Model_Year_76 + Model_Year_82
Estimated Coefficients:
Estimate SE tStat pValue
________ _______ ______ __________
Model_Year_70 17.69 1.0328 17.127 3.2371e-30
Model_Year_76 21.574 0.95387 22.617 4.0156e-39
Model_Year_82 31.71 0.99896 31.743 5.2234e-51
Number of observations: 94, Error degrees of freedom: 91
Root Mean Squared Error: 5.56
Choose Reference Level in Model
You can choose a reference level by modifying the order of categories in a categorical variable. First, create a categorical variable Year.
Year = categorical(Model_Year);
Check the order of categories by using the categories function.
categories(Year)
ans = 3×1 cell
{'70'}
{'76'}
{'82'}
If you use Year as a predictor variable, then fitlm chooses the first category '70' as a reference level. Reorder Year by using the reordercats function.
Year_reordered = reordercats(Year,{'76','70','82'});
categories(Year_reordered)ans = 3×1 cell
{'76'}
{'70'}
{'82'}
The first category of Year_reordered is '76'. Create a linear regression model of MPG as a function of Year_reordered.
mdl2 = fitlm(Year_reordered,MPG,'VarNames',{'Model_Year','MPG'})
mdl2 =
Linear regression model:
MPG ~ 1 + Model_Year
Estimated Coefficients:
Estimate SE tStat pValue
________ _______ _______ __________
(Intercept) 21.574 0.95387 22.617 4.0156e-39
Model_Year_70 -3.8839 1.4059 -2.7625 0.0069402
Model_Year_82 10.136 1.3812 7.3385 8.7634e-11
Number of observations: 94, Error degrees of freedom: 91
Root Mean Squared Error: 5.56
R-squared: 0.531, Adjusted R-Squared: 0.521
F-statistic vs. constant model: 51.6, p-value = 1.07e-15
mdl2 uses '76' as a reference level and includes two indicator variables and .
Evaluate Categorical Predictor
The model display of mdl2 includes a p-value of each term to test whether or not the corresponding coefficient is equal to zero. Each p-value examines each indicator variable. To examine the categorical variable Model_Year as a group of indicator variables, use anova. Use the 'components'(default) option to return a component ANOVA table that includes ANOVA statistics for each variable in the model except the constant term.
anova(mdl2,'components')ans=2×5 table
SumSq DF MeanSq F pValue
______ __ ______ _____ __________
Model_Year 3190.1 2 1595.1 51.56 1.0694e-15
Error 2815.2 91 30.936
The component ANOVA table includes the p-value of the Model_Year variable, which is smaller than the p-values of the indicator variables.
Input Arguments
Linear regression model object, specified as a LinearModel object created by using fitlm or stepwiselm, or a CompactLinearModel object created by using compact.
ANOVA type, specified as one of these values:
'component'—anovareturns the tabletblwith ANOVA statistics for each variable in the model except the constant term.'summary'—anovareturns the tabletblwith summary ANOVA statistics for grouped variables and the model as a whole.
For details, see the tbl output argument
description.
Sum of squares type for each term, specified as one of the values in this table.
| Value | Description |
|---|---|
1 | Type 1 sum of squares — Reduction in residual sum of squares obtained by adding the term to a fit that already includes the preceding terms |
2 | Type 2 sum of squares — Reduction in residual sum of squares obtained by adding the term to a model that contains all other terms |
3 | Type 3 sum of squares — Reduction in residual sum of squares obtained by adding the term to a model that contains all other terms, but with their effects constrained to obey the usual “sigma restrictions” that make models estimable |
'h' | Hierarchical model — Similar to Type 2, but uses both continuous and categorical factors to determine the hierarchy of terms |
The sum of squares for any term is determined by comparing two models. For a model containing
main effects but no interactions, the value of sstype influences the
computations on unbalanced data only.
Suppose you are fitting a model with two factors and their interaction, and the terms appear in the order A, B, AB. Let R(·) represent the residual sum of squares for the model. So, R(A, B, AB) is the residual sum of squares fitting the whole model, R(A) is the residual sum of squares fitting the main effect of A only, and R(1) is the residual sum of squares fitting the mean only. The three sum of squares types are as follows:
| Term | Type 1 Sum of Squares | Type 2 Sum of Squares | Type 3 Sum of Squares |
|---|---|---|---|
A | R(1) – R(A) | R(B) – R(A, B) | R(B, AB) – R(A, B, AB) |
B | R(A) – R(A, B) | R(A) – R(A, B) | R(A, AB) – R(A, B, AB) |
AB | R(A, B) – R(A, B, AB) | R(A, B) – R(A, B, AB) | R(A, B) – R(A, B, AB) |
The models for Type 3 sum of squares have sigma restrictions imposed. This means, for example, that in fitting R(B, AB), the array of AB effects is constrained to sum to 0 over A for each value of B, and over B for each value of A.
For Type 3 sum of squares:
If
mdlis aCompactLinearModelobject and the regression model is nonhierarchical,anovareturns an error.If
mdlis aLinearModelobject and the regression model is nonhierarchical,anovarefits the model using effects coding whenever it needs to compute a Type 3 sum of squares.If the regression model in
mdlis hierarchical,anovacomputes the results without refitting the model.
sstype applies only if anovatype
is 'component'.
Output Arguments
ANOVA summary statistics table, returned as a table.
The contents of tbl depend on the ANOVA type
specified in anovatype.
If
anovatypeis'component', thentblcontains ANOVA statistics for each variable in the model except the constant (intercept) term. The table includes these columns for each variable:Column Description SumSqSum of squares explained by the term, computed depending on
sstypeDFDegrees of freedom
DFof a numeric variable is 1.DFof a categorical variable is the number of indicator variables created for the category (number of categories – 1). Note thattblcontains one row for each categorical variable instead of one row for each indicator variable as in the model display. Useanovato test a categorical variable as a group of indicator variables.DFof an error term is n – p, where n is the number of observations and p is the number of coefficients in the model.
MeanSqMean square, defined by
MeanSq=SumSq/DFMeanSqfor the error term is the mean squared error (MSE).FF-statistic value to test the null hypothesis that the corresponding coefficient is zero, computed by
F=MeanSq/MSEWhen the null hypothesis is true, the F-statistic follows the F-distribution. The numerator degrees of freedom is the
DFvalue for the corresponding term, and the denominator degrees of freedom is n – p.pValuep-value of the F-statistic value
For an example, see Component ANOVA Table.
If
anovatypeis'summary', thentblcontains summary statistics of grouped terms for each row. The table includes the same columns as'component'and these rows:Row Description TotalTotal statistics
SumSq— Total sum of squares, which is the sum of the squared deviations of the response around its meanDF— Sum of degrees of freedom ofModelandResidual
ModelStatistics for the model as a whole
SumSq— Model sum of squares, which is the sum of the squared deviations of the fitted value around the response mean.FandpValue— These values provide a test of whether the model as a whole fits significantly better than a degenerate model consisting of only a constant term.
If
mdlincludes only linear terms, thenanovadoes not decomposeModelintoLinearandNonLinear.LinearStatistics for linear terms
SumSq— Sum of squares for linear terms, which is the difference between the model sum of squares and the sum of squares for nonlinear terms.FandpValue— These values provide a test of whether the model with only linear terms fits better than a degenerate model consisting of only a constant term.anovauses the mean squared error that is based on the full model to compute this F-value, so the F-value obtained by dropping the nonlinear terms and repeating the test is not the same as the value in this row.
NonlinearStatistics for nonlinear terms
SumSq— Sum of squares for nonlinear (higher-order or interaction) terms, which is the increase in the residual sum of squares obtained by keeping only the linear terms and dropping all nonlinear terms.FandpValue— These values provide a test of whether the full model fits significantly better than a smaller model consisting of only the linear terms.
ResidualStatistics for residuals
SumSq— Residual sum of squares, which is the sum of the squared residual valuesMeanSq— Mean squared error, used to compute the F-statistic values forModel,Linear, andNonLinear
If
mdlis a fullLinearModelobject and the sample data contains replications (multiple observations sharing the same predictor values), thenanovadecomposes the residual sum of squares into a sum of squares for the replicated observations (Lack of fit) and the remaining sum of squares (Pure error).Lack of fitLack-of-fit statistics
SumSq— Sum of squares due to lack of fit, which is the difference between the residual sum of squares and the replication sum of squares.FandpValue— The F-statistic value is the ratio of lack-of-fitMeanSqto pure errorMeanSq. The ratio provides a test of bias by measuring whether the variation of the residuals is larger than the variation of the replications. A low p-value implies that adding additional terms to the model can improve the fit.
Pure errorStatistics for pure error
SumSq— Replication sum of squares, obtained by finding the sets of points with identical predictor values, computing the sum of squared deviations around the mean within each set, and pooling the computed valuesMeanSq— Model-free pure error variance estimate of the response
For an example, see Summary ANOVA Table.
Alternative Functionality
More complete ANOVA statistics are available in the anova1, anova2, and anovan functions.
Extended Capabilities
This function fully supports GPU arrays. For more information, see Run MATLAB Functions on a GPU (Parallel Computing Toolbox).
Version History
Introduced in R2012a
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