calling all the elements of a matrix consecutively

I need to call every element of a vector consecutively except the 'i' element I'm on. for example if i am using two for loops and my vector is V = [1,2,3,4,5]

[n,m]=size(V)

 for i=1:m 

   for j=1:m-1

when i=1, i need to call 2 then 3 then 4 then 5

but for example when i=4, I need to call 1 then 2 then 3 then 5

I need this to work for any size vector because i am going to try to implement this in my Lagrangian polynomial interpolation function.

so again an example for i=3, my four j's in the second for loop should be 1 then 2 then 4 then 5

[Azzi Abdelmalek]

what do you mean by call?

[Nicholas]

I just mean for my second for loop each iteration has to be a consecutive value from my vector V, skipping whatever value is in the ith place for my first for loop...for example for i = 3 I need my second for loop to iterate 1 then 2 then 4 then 5....let me know if this doesnt make sense.

[Nicholas]

here is another example...

V = [ 1 4 9 5]

[n,m]=size(V)

 for i=1:m  % m equals the number of values in my vector

   for j=1:m-1

    when i is 1, my second for loop needs to iterate 4 then 9 then 5

    when i is 2 my second for loop needs to iterate 1 then 9 then 5

Answer 1

[Azzi Abdelmalek]

V = [ 1 4 9 5]
for ii=1:numel(V)
   q=V;
   q(ii)=[]
   for jj=q

[Nicholas]

AWESOME! thank you very much