loop to create the new matrix which contains the kron product

Hi,

So I have created a 3*3 matrix for A and B as shown below

A=round(rand(3,3)*10-5)

B=round(rand(3,3)*20-10)

now the question has ask me to use the nested loop to create the new matrix which contains the Kronecker product K=A*B

for i=1:3
    for ii=1:3
        K=A(i,ii)*B
    end
end

I've attempted to do this by creating this nested loop, it generates 9 answers for K and I don't really know how to combine these answers into one matrix of 9*9. I am not sure if this method is right. It would be great if anyone can help me with this.

Thank you in advance :)

Answer 1

[Roger Stafford]

 K = zeros(3*3,3*3);
 for i=1:3
    for ii=1:3
       K(3*i-2:3*i,3*ii-2:3*ii) = A(i,ii)*B;
    end
 end

[Kantosa]

Thank you :)

Answer 2

[sixwwwwww]

you can do it as follows:

A = round(rand(3,3)*10-5);
B = round(rand(3,3)*20-10);
for i = 1:size(A, 1)
    for j = 1:size(A, 2)
        AB{i, j} = A(i, j) * B;
    end
end
AB = cell2mat(AB);
disp(AB)

Good luck!

[Kantosa]

Thank you :)

[sixwwwwww]

you are welcome