Working of interpolation or decimation
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Gova ReDDy
el 9 de En. de 2014
Editada: Gova ReDDy
el 16 de En. de 2014
Hello,
Can someone explain how the interpolation or decimation can be used to fit the number of samples between the two signals if both the signals doesn't have the same number of samples.
Thanks.
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Image Analyst
el 9 de En. de 2014
See this demo:
% Make signal #1
t1 = linspace(-2*pi, 2*pi, 200);
period = 1.5;
y1 = sin(2*pi*t1/period);
plot(t1, y1, 'bo-', 'LineWidth', 6, 'MarkerSize', 20);
grid on;
% Enlarge figure to full screen.
set(gcf, 'units','normalized','outerposition',[0 0 1 1]);
% Make signal #2
t2 = linspace(-2*pi, 2*pi, 130);
period = 1.5;
y2 = sin(2*pi*t2/period);
hold on;
plot(t2, y2, 'ys-', 'LineWidth', 4);
% Interpolate signal 2 up to have same number of samples as signal 1
y2Interp = interp1(t2, y2, t1);
plot(t1, y2Interp, 'rd-', 'LineWidth', 2);
legend('signal 1', 'signal 2', 'signal 2 interpolated');
% Now get signal half way between the signal #1
% and the interpolated signal #2
signal3 = 0.5 * y1 + 0.5 * y2Interp;
I trust you can do the case where you want to interpolate y1 down to the lesser number of samples that y2 has - it's straightforward.
6 comentarios
Image Analyst
el 16 de En. de 2014
You're not using interp correctly - look at the first two input arguments - they are the same and they should not be.
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