number format change in axes of graphs
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I find that numbers on axes will be automatically displayed by common scale factor such as n power of ten when plotting a figure. It seems that n is usually 3 or bigger in absolute. Is it possible to scale it down to 2?
For example, 150 will be automatically displayed as 0.15 as the tick number with 10^3 on top of the y-axis, but it is expected to be 1.5 with 10^2 on top.
But I don't know how to realize it by code?
Could someone have a say? Thank you in advance.
1 comentario
Respuestas (4)
Bruno Pop-Stefanov
el 20 de En. de 2014
1 voto
Please refer to this previous post for formatting tick labels:
3 comentarios
Bruno Pop-Stefanov
el 22 de En. de 2014
I did some research and tested myself and apparently, there is no way to control the value of the exponent that MATLAB automatically generates (at least in the current releases).
What you could do instead is label the ticks manually with get and set and play with the exponent:
x = 1:0.1:1000;
y = linspace(-0.005, 0.005, numel(x));
% Find a negative exponent
n = 0;
lpart = floor(max(y));
while lpart == 0
n = n+1;
lpart = floor(10^n * max(y));
end
n = -n;
figure;
plot(x,y)
y_tick = str2num(get(gca, 'YTickLabel'));
set(gca, 'YTickLabel', sprintf('%.e|', y_tick*10^n))
I haven't figured a way to format "0.5e-02" instead of "5.0e-03"... Sorry I can't help you more.
LIU
el 22 de En. de 2014
Walter Roberson
el 20 de En. de 2014
0 votos
Set yticklabel to the printable representation of the values you want; that will prevent the scale factor from being generated.
1 comentario
Juan Andrés Martin
el 5 de Nov. de 2020
Editada: Walter Roberson
el 6 de Nov. de 2020
Refer to "Specify Axis Tick Values and Labels" in Matlab Documentation, specifically "Control Value in Exponent Label Using Ruler Objects" paragraph.
Moreover, using Bruno Pop-Stefanov's code as a basis:
x = 1:0.1:1000;
y = linspace(-0.005, 0.005, numel(x));
plot(x,y)
ax=gca;
ax.YAxis.Exponent=-2;
That should do the trick
1 comentario
Walter Roberson
el 6 de Nov. de 2020
Note that this requires R2015b or newer.
If I recall correctly, there was also a way to do it in R2015a, but the axis property names were different -- YRuler instead of YAxis I think it was.
Paulo Providencia
el 17 de Mzo. de 2026 a las 19:01
Editada: Walter Roberson
el 17 de Mzo. de 2026 a las 20:36
0 votos
This proposal has worked for me: https://superuser.com/questions/1206634/matlab-how-to-put-the-same-number-of-decimal-places-in-the-axes
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