How to do segmentation for detecting microaneurysms?
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hi, please help me. i want to create a program for the detection of microaneuryms in diabetic retinopathy diseases. i have retinal image and success doing vascular segmentation. the point is, i've been using a region growing from http://www.mathworks.com/matlabcentral/fileexchange/32532-region-growing-2d3d-grayscale but it just give me one object of microaneurysm like this
i want the result like this
this is my original image after using adaptive histogram
what should i do? or is there a recommended method that i can use?
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Respuestas (2)
Nitin
el 16 de Feb. de 2014
Hope this gets you started:
I=imread('retinal.PNG'); I2 = rgb2gray(I); I_bin = I2>150;
In the next step, you can choose the smaller regions you are interested in using bwselect and or regionsprops based on your criteria
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Image Analyst
el 16 de Feb. de 2014
Editada: Image Analyst
el 3 de Sept. de 2021
People have done this before and published their methods. Look for them in section 20.5 here:
Most likely, you'll find robust algorithms won't be just a hundred or two hundred lines long, as I don't expect that it's a simple problem.
A quick and dirty, non-robust method would be something like this
- threshold image
- find areas and perimeters
- remove largest region (the main vessel network)
- compare circularities (Perimeter^2/(4*pi*area)) of remaining regions and keep regions with low circularity values to keep compact blobs rather than stick-like blobs.
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Mustapha Seidu
el 3 de Sept. de 2021
Hi, this is the second time I am coming across this link today. Can you provided an updated link pls? This particular one has nothing relating to the problem. Thank you.
Image Analyst
el 3 de Sept. de 2021
Where was the first one, if you still remember. Obviously the link worked once but I guess they changed it from
http://iris.usc.edu/Vision-Notes/bibliography/contentsmedical.html#Medical%20Applications,%20CAT,%20MRI,%20Ultrasound,%20Heart%20Models,%20Brain%20Models
to the new link:
I'll change it in my original answer also.
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