No solution found using fsolve

2 visualizaciones (últimos 30 días)
BITS
BITS el 12 de Mzo. de 2014
Editada: Matt J el 12 de Mzo. de 2014
My fsolve function is
F=[e11*(x(1)-Vwt)+e12*(x(2)-p)*10^6-(qf-qs)*dt;...
e21*(x(1)-Vwt)+e22*(x(2)-p)*10^6-(Q+qf*hf-qs*hs)*dt;...
e32*(x(2)-p)+e33*(x(3)-ar)-(Q-ar*hc*qdc)*dt;...
e42*(x(2)-p)*10^6+e43*(x(3)-ar)+e44*(x(4)-Vsd)-(Ps*(Vsd0-Vsd)/Td)*dt-((hf-hw)/hc)*dt];
The error shown is
Norm of First-order Trust-region
Iteration Func-count f(x) step optimality radius
0 5 1.03051e+033 1.21e+032 1
1 10 8.02298e+032 1 1.07e+032 1
2 15 3.56576e+032 2.5 7.13e+031 2.5
3 20 2.32352e+019 4.99999 7.09e+023 6.25
4 25 1.41731e+019 12.5 3.28e+020 12.5
5 30 1.28804e+018 31.2499 2.06e+021 31.2
6 35 14064.4 13.4862 4.48e+017 78.1
7 40 5.22757 1.22008e-006 8.63e+015 78.1
8 41 5.22757 1.2766e-014 8.63e+015 78.1
No solution found.
fsolve stopped because the relative size of the current step is less than the default value of the step size tolerance squared, but the vector of function values is not near zero as measured by the default value of the function tolerance.
criteria details please help

Respuesta aceptada

Alan Weiss
Alan Weiss el 12 de Mzo. de 2014
I don't know what is going on with your function, but did you try the suggestions in the documentation?
Alan Weiss
MATLAB mathematical toolbox documentation

Más respuestas (1)

Matt J
Matt J el 12 de Mzo. de 2014
Editada: Matt J el 12 de Mzo. de 2014
Since the equations are linear in the x(i) you should probably be using MLDIVIDE instead of FSOLVE.

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