Plots for second order control system in the same graph

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Carlos
Carlos el 25 de Mzo. de 2014
Editada: Paul el 30 de Mzo. de 2014
I'm been trying to graph this equation without success.I keep getting an error message that says:Warning: Imaginary parts of complex X and/or Y arguments ignored.
Note: input is in radiant.
Here is my code:
% Exersice 11
x = input('Please enter vector x in degree: ');
z = [0.1 0.2 0.4 0.7 0.9];
y1 = 1-1/sqrt(1-z(1,1).^2).*exp(-z(1,1).*x).*sin(sqrt(1-z(1,1).^2)).*x+acos(x);
y2 = 1-1/sqrt(1-z(1,2).^2).*exp(-z(1,2).*x).*sin(sqrt(1-z(1,2).^2)).*x+acos(x);
y3 = 1-1/sqrt(1-z(1,3).^2).*exp(-z(1,3).*x).*sin(sqrt(1-z(1,3).^2)).*x+acos(x);
y4 = 1-1/sqrt(1-z(1,4).^2).*exp(-z(1,4).*x).*sin(sqrt(1-z(1,4).^2)).*x+acos(x);
y5 = 1-1/sqrt(1-z(1,5).^2).*exp(-z(1,5).*x).*sin(sqrt(1-z(1,5).^2)).*x+acos(x);
plot(x,y1,x,y2,x,y3,x,y4,x,y5, 'm'), xlabel('x in radiands'), ylabel('y(x)') ,title('1-1/{\surd}(1-\zeta^2)e^-^\zeta^xsin{\surd}(1-\zeta^2)x+cos^-^1(x)'), grid, legend('\zeta = 0.1','\zeta = 0.2','\zeta = 0.4','\zeta = 0.7','\zeta = 0.9')
  2 comentarios
Azzi Abdelmalek
Azzi Abdelmalek el 25 de Mzo. de 2014
What is the problem?
Carlos
Carlos el 25 de Mzo. de 2014
I should get a sinusoidal graph for each zeta plugged in and what I'm getting is a strange line.
See attached screenshots
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Respuesta aceptada

Paul
Paul el 30 de Mzo. de 2014
Editada: Paul el 30 de Mzo. de 2014
Two things are wrong. One is the parenthesis before .x which should be on the end. The second is the acos(x) which should be acos(z(...)). Also it doesnt make sense that you ask x in degrees while it should be radians:
x = input('Please enter vector x in radians: ');
z = [0.1 0.2 0.4 0.7 0.9];
y1 = 1-(1/sqrt(1-z(1,1).^2)).*exp(-z(1,1).*x).*sin(sqrt(1-z(1,1).^2).*x+acos(z(1,1)));
y2 = 1-1/sqrt(1-z(1,2).^2).*exp(-z(1,2).*x).*sin(sqrt(1-z(1,2).^2).*x+acos(z(1,2)));
y3 = 1-1/sqrt(1-z(1,3).^2).*exp(-z(1,3).*x).*sin(sqrt(1-z(1,3).^2).*x+acos(z(1,3)));
y4 = 1-1/sqrt(1-z(1,4).^2).*exp(-z(1,4).*x).*sin(sqrt(1-z(1,4).^2).*x+acos(z(1,4)));
y5 = 1-1/sqrt(1-z(1,5).^2).*exp(-z(1,5).*x).*sin(sqrt(1-z(1,5).^2).*x+acos(z(1,5)));
figure;
plot(x,y1,x,y2,x,y3,x,y4,x,y5, 'm'), xlabel('x in radiands'), ylabel('y(x)') ,title('1-1/{\surd}(1-\zeta^2)e^-^\zeta^xsin{\surd}(1-\zeta^2)x+cos^-^1(x)'), grid, legend('\zeta = 0.1','\zeta = 0.2','\zeta = 0.4','\zeta = 0.7','\zeta = 0.9')
It would also be easier to just use z(2) instead of z(1,2) etc. and using a for loop like Mischa suggested would save you the copy paste code.

Más respuestas (1)

Mischa Kim
Mischa Kim el 26 de Mzo. de 2014
Editada: Mischa Kim el 26 de Mzo. de 2014
Carlos, check out
function myDE()
prompt = {'xmin:','xmax:'};
name = 'Input x-range';
numlines = 1;
xlimits = inputdlg(prompt,name,numlines);
N = 100;
x = linspace(str2num(xlimits{1}),str2num(xlimits{2}),N);
z = [0.1 0.2 0.4 0.7 0.9];
hold all
for ii = 1:numel(z)
y = 1 - (1/sqrt(1-z(ii)^2))*exp(-z(ii)*x).*sin(sqrt(1-z(ii)^2)*x...
+ acos(z(ii)));
plot(x,y)
end
end
  1 comentario
Carlos
Carlos el 29 de Mzo. de 2014
This is beyond my course scope. Could you simplify using more or less what I have above?
Thanks.

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