How to generate uniformly distributed random integers?

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I've been using "ceil(4*rand)" to generate random integers from 1 to 4. But when I tried to check the uniformity, I found that I do not get a probability of 0.25 and instead have p(1)=0.24997, p(2)=0.25102, p(3)=0.24949 and p(4)=0.24951 after generating 10,00,000 values. Is it good enough to say that it's uniform?

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the cyclist
the cyclist el 25 de Jul. de 2011
Yes. You should not expect to get exactly 25% of each, every time. That is expected behavior of random numbers.
FYI, it may be more convenient for you to use the randi() function to do what you are doing.
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Walter Roberson
Walter Roberson el 25 de Jul. de 2011
the cyclist is correct. Please see also the description in http://www.mathworks.com/matlabcentral/answers/12307-how-to-generate-a-uniform-random-variable-in-the-interval-1-1-with-mean-zero

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Más respuestas (2)

Pannir Selvam Elamvazhuthi
Pannir Selvam Elamvazhuthi el 28 de Ag. de 2011
Thanks Cyclist and Walter Roberson. Sorry to have responded late.
  1 comentario
the cyclist
the cyclist el 29 de Ag. de 2011
No problem on the late response. However, you should consider deleting this "answer" (because it is not answer), and making it a comment on my answer.

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Sergio Enrique Pinto Castillo
Sergio Enrique Pinto Castillo el 28 de Jul. de 2020
Editada: Sergio Enrique Pinto Castillo el 28 de Jul. de 2020
I think the answer is:
Num = 1000;
vec = randi([1 Num],1,Num);
This instruction generate a vector with random uniformly distributed integers between 1 and 1000

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