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Cos^2(2theta) 3d polar graph in MATLAB

13 visualizaciones (últimos 30 días)
Tracy Colbert
Tracy Colbert el 14 de Sept. de 2021
Respondida: Harshvardhan el 9 de Mzo. de 2023
How do i graph cos^2(2theta) in 3d ploar grpah? in MATLAB
Cos^2(2theta) where 0=<theta=<90 and 0=<phi=<360
  5 comentarios
Tracy Colbert
Tracy Colbert el 14 de Sept. de 2021
Literally this is all ive been given, i know it is supposed to look like a dome
David Goodmanson
David Goodmanson el 14 de Sept. de 2021
Editada: David Goodmanson el 16 de Sept. de 2021
Hello Tracy,
Assume that theta and phi have the usual convention for spherical coordinates,
x = r*sin(theta)*cos(phi) y = r*sin(theta)*sin(phi) z = r*cos(theta)
Then if the intent is r = constant, and new z = f(theta), it seems more likely that the function would be cos^2(theta). This will give something that is axially symmetric around the z axis and looks like the end of a football. But If the intent is r = f(theta) and z defined in the usual way, then cos^2(2*theta) works but does not look like a dome. Does any of the material you have mention the meshgrid function, or plotting using surf?

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Respuestas (2)

Walter Roberson
Walter Roberson el 15 de Sept. de 2021
Editada: Walter Roberson el 15 de Sept. de 2021
%0=<theta=<90 and 0=<phi=<360
[Theta, Phi] = meshgrid(linspace(0,90,361), linspace(0,360,361));
%cos^2(2theta)
R = cosd(2*Theta).^2;
[X, Y, Z] = sph2cart(Theta, Phi, R);
surf(X, Y, Z, 'edgecolor', 'none')
xlabel('X'); ylabel('Y')
  2 comentarios
Tracy Colbert
Tracy Colbert el 15 de Sept. de 2021
Thank you very much!!!
Walter Roberson
Walter Roberson el 16 de Sept. de 2021
I forgot to account for degrees.
%0=<theta=<90 and 0=<phi=<360
[Theta, Phi] = meshgrid(linspace(0,90,361), linspace(0,360,361));
%cos^2(2theta)
R = cosd(2*Theta).^2;
[X, Y, Z] = sph2cart(Theta*pi/180, Phi*pi/180, R);
surf(X, Y, Z, 'edgecolor', 'none')
xlabel('X'); ylabel('Y')

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Harshvardhan
Harshvardhan el 9 de Mzo. de 2023
% Define theta and r vectors
theta = linspace(0, 2*pi, 360);
r = cos(2*theta).^2;
% Convert polar coordinates to Cartesian coordinates
x = r.*cos(theta);
y = r.*sin(theta);
z = r;
% Plot 3D polar graph
plot3(x, y, z)
title('3D Polar Graph of cos^2(2\theta)')
xlabel('x-axis')
ylabel('y-axis')
zlabel('z-axis')

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