How to Plot a graph with restriction?

Hi,
I am sorry I am new to MATLAB and dont know how to exactly formulate my quetsion.
I want to plot a graph between two variables but I want to restrict the plot area with a third varible. For example:
x = (0.5*pi:0.1:6*pi) y = sin(x)
Plot (x,y)
but now i want to restrict my plot with the following variable:
z = (pi:0.1;2*pi)
Note: The divisions are same for 'x' and 'z'.
Thanks, Mustahsan

 Respuesta aceptada

Mischa Kim
Mischa Kim el 15 de Sept. de 2014
Mustahsan, what do you mean by restrict? Setting the plotting limits? Something like:
xlim([pi, 2*pi])

5 comentarios

Mischa Kim
Mischa Kim el 16 de Sept. de 2014
Editada: Mischa Kim el 16 de Sept. de 2014
Use, e.g.,
x = (0.5*pi:0.1:6*pi);
y = sin(x);
z = [pi; 2*pi];
plot(x(x>z(1) & x<z(2)), y(x>z(1) & x<z(2)))
For z you really only need the limits.
Please add follow-up questions and comments as such and not as answers to keep the thread readable.
Sory for replying on the answer section!
Okay following is what i typed, which niether gives me a figure nor a graph
plot(n(n>POS_thr(95) & n<POS_thr(100)), M_ISO(M_ISO>POS_thr(95) & M_ISO<POS_thr(100)))
Where POS_thr is a variable and I want to plot n & M_ISO but with the restriction that POS_thr should only be between 95 and 100.
I hope you get my point!
Since I do not know what your variables are, check out
x = (0.5*pi:0.01:6*pi);
y = sin(x);
z = 2*cos(x).^2;
plot(x,y,x,z)
hold on
plot(x(z>0.5 & z<0.8), y(z>0.5 & z<0.8),'or')
z needs to be within [0.5 0.8] for the second plot.
Mustahsan Majeed
Mustahsan Majeed el 16 de Sept. de 2014
All the three variables are attached with this reply. All three have same number of rows but I only want to plot 'n' against 'M_ISO' using only those rows where 'POS_thr' is between 95 to 100.
Use
plot(n(POS_thr>=95 & POS_thr<=100), M_ISO(POS_thr>=95 & POS_thr<=100),'or');

Iniciar sesión para comentar.

Más respuestas (1)

Michael Haderlein
Michael Haderlein el 15 de Sept. de 2014
Dear Mustahsan,
not sure if that's what you mean, but please check for
xlim([pi 2*pi])
Best regards, Michael

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