Integrating a 2nd order ODE

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PetronasAMG
PetronasAMG el 16 de Oct. de 2021
Respondida: Star Strider el 17 de Oct. de 2021
I am given an equation,
d^2y/dx^2 + q(x) = 0
x ranges from 0 to 1 and y(0) = 1 and y(L) = 1.5
where L = 1
and q(x) = 2*cos((pi*x)/L)
here is what I have
function dydx = yfunc (x,y)
x = linspace(0,1,30);
L = 1;
for i = 1:length(x)
qx(i)= 2*cos((pi*x(i))/L);
end
dydx= -qx;
end
%main script
[x,y] = ode45(@yfunc,x,[1 1.5]);
I am running into an error stating Dimensions of arrays being concatenated are not consistent. Could you please help me?

Respuesta aceptada

Star Strider
Star Strider el 17 de Oct. de 2021
This is a boundary value problem. Use bvp4c to solve it.
syms y(x) x L Y
q(x) = 2*cos(pi*x/L);
Dy = diff(y);
D2y = diff(Dy);
ODE = D2y + q
ODE(x) = 
[VF,Subs] = odeToVectorField(ODE)
VF = 
Subs = 
bvpfcn = matlabFunction(VF, 'Vars',{x,Y,L})
bvpfcn = function_handle with value:
@(x,Y,L)[Y(2);cos((x.*pi)./L).*-2.0]
I solved it completely, however I do not want to deprive you of the same feeling of accomplishment, so I leave the rest to you. It is a straightforward solution. Follow the examples in the documentation I linked to.
.

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