approximating pi with taylor series expansion to the 10,000th term

This was my code: I=0

while (I<10000)

I=((-1)^I)/(2*I+1)

end

x=4*I

so when I do that the answer shows as

x =

      NaN +    NaNi

Answer 1

[Mischa Kim]

charlotte, you are almost there:

 l = 1;
 for ii = 1:10000
    l = l + ((-1)^ii)/(2*ii + 1);
 end
 x = 4*l;

• If the number of iterations (series terms) is know, use a for-loop
• ii is the loop index, l is the approximation to pi/4