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who can create a surf y=0 in a defined domain?

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Moein
Moein el 3 de Oct. de 2014
Comentada: Stephen23 el 3 de Oct. de 2014
hi friends
i want to create a surf y=0 in a domain by surf and linspace functions with this code:
hsp = surf(linspace(-0.3,1.3,200),zeros(200)+0.125,linspace(-0.251776695,0.501776695,200));
but it errors.
for the case z=0 the following code is correct:
hsp = surf(linspace(-0.3,1.3,200),linspace(-0.251776695,0.501776695,200),zeros(200)+0.125);
but for y=0 it errors:
Z must be a matrix, not a scalar or vector.
help me if you can.
thanks a lot
  2 comentarios
John D'Errico
John D'Errico el 3 de Oct. de 2014
Don't just keep on asking the same question!
Stephen23
Stephen23 el 3 de Oct. de 2014
Please stop double posting (or in your case, triple posting).
If you wish to make people aware of your question, you only need to add a comment to the original question and it come to the front of the list.
Imagine other readers here: we don't know what advice you already have become on the other posts of the same question, and we are not paid to find all three posts of your identical question, compare the current best answers and see if we can add anything better.

Respuesta aceptada

Mike Garrity
Mike Garrity el 3 de Oct. de 2014
The 3rd arg to surf needs to be 2D. That's optional for the other two. You can use meshgrid to expand your 1D arrays out to 2D like this:
[x,z]=meshgrid(linspace(-0.3,1.3,200),linspace(-0.251776695,0.501776695,200));
surf(x,zeros(200)+.125,z)

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