function to increase the range of inverse sine
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The asin() function only returns values between (-pi/2, pi/2). How can I write a function to give me values between (0, 2pi)?
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Respuestas (3)
  Walter Roberson
      
      
 el 14 de Sept. de 2011
        1 comentario
  Jan
      
      
 el 14 de Sept. de 2011
				This will solve the problem by using the MATLAB 2013a or later. Not very efficient...
  the cyclist
      
      
 el 14 de Sept. de 2011
        You can force the output to be within the range (0,2pi) by applying the mod() function:
>> mod(asin(x),2*pi)
Given only one input argument, you can't infer precisely which quadrant to return. Walter's answer points to a list of requested features (specifically, more two-argument versions of inverse trig functions).
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  theodore panagos
 el 26 de Oct. de 2018
        
      Editada: Walter Roberson
      
      
 el 26 de Oct. de 2018
  
      You can have the asin(x,y) from 0 to 2*pi by the formula:
asin(x,y)=pi-pi/2*(1+sgn(x))*(1-sgn(y^2))-pi/4*(2+sgn(x))*sgn(y) -sgn(x*y)*asin((abs(x)-abs(y))/sqrt(2*x^2+2*y^2))
there is x=x2-x1 and y=y2-y1
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