from a python code to matlab code

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Michael Angeles
Michael Angeles el 30 de Dic. de 2021
Comentada: Michael Angeles el 31 de Dic. de 2021
how can I convert the following code to matlab code?
cuts_under_30 = [hairstyles[i] for i in range(len(hairstyles)) if new_prices[i] < 30]
print("Cuts under 30: " "{}".format(cuts_under_30))

Respuesta aceptada

Image Analyst
Image Analyst el 31 de Dic. de 2021
Try this:
clc; % Clear the command window.
close all; % Close all figures (except those of imtool.)
clear; % Erase all existing variables. Or clearvars if you want.
%workspace; % Make sure the workspace panel is showing.
format short g;
format compact;
fontSize = 20;
hairstyles = {'bouffant', 'pixie', 'dreadlocks', 'crew', 'bowl', 'bob', 'mohawk', 'flattop'};
prices = [30, 25, 40, 20, 20, 35, 50, 35];
last_week = [2, 3, 5, 8, 4, 4, 6, 2];
%my code
total_price = 0;
for price = 1:length(prices)
total_price = total_price + prices(price);
end
disp(total_price);
255
average_price = total_price/numel(prices);
fprintf('Average Hair Cut Price is: %.3f\n', average_price);
Average Hair Cut Price is: 31.875
%problem #5
new_prices = prices()-5;
disp(new_prices);
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%fprintf('The new prices are: %.2f\n', new_prices);
%Revenue
total_revenue = 0;
total_revenue = sum(prices.*last_week);
fprintf('Total Revenue is: %.f\n', total_revenue);
Total Revenue is: 1085
%average revenue
average_revenue = total_revenue/7;
fprintf('The average revenue is: %.f\n', average_revenue)
The average revenue is: 155
% cuts_under_30 = [hairstyles[i] for i in range(len(hairstyles)) if new_prices[i] < 30]
indexes = new_prices < 30;
cuts_under_30 = hairstyles(indexes)
cuts_under_30 = 1×4 cell array {'bouffant'} {'pixie'} {'crew'} {'bowl'}
prices_under_30 = new_prices(indexes)
prices_under_30 = 1×4
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fprintf('Cuts under 30 :\n')
Cuts under 30 :
for k = 1 : length(prices_under_30)
fprintf('%s costs $%.2f\n', cuts_under_30{k}, prices_under_30(k));
end
bouffant costs $25.00 pixie costs $20.00 crew costs $15.00 bowl costs $15.00
fprintf('\n')
  1 comentario
Michael Angeles
Michael Angeles el 31 de Dic. de 2021
Thank you so much...was trying to figure that out for a while...

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Más respuestas (2)

Chunru
Chunru el 31 de Dic. de 2021
% cuts_under_30 = [hairstyles[i] for i in range(len(hairstyles)) if new_prices[i] < 30]
cuts_under_30 = hairstyles(new_prices < 30);
  3 comentarios
Chunru
Chunru el 31 de Dic. de 2021
Or simply remove the semicolon at the end of the statement.
Michael Angeles
Michael Angeles el 31 de Dic. de 2021
Editada: Image Analyst el 31 de Dic. de 2021
It didn't work....Here is the whole code I am working on from Python...
hairstyles = ["bouffant", "pixie", "dreadlocks", "crew", "bowl", "bob", "mohawk", "flattop"];
prices = [30, 25, 40, 20, 20, 35, 50, 35];
last_week = [2, 3, 5, 8, 4, 4, 6, 2];
%my code
total_price = 0;
for price = 1:length(prices)
total_price = total_price + prices(price);
end
disp(total_price);
average_price = total_price/numel(prices);
fprintf("Average Hair Cut Price is: %.3f\n", average_price);
%problem #5
new_prices = prices()-5;
disp(new_prices);
%fprintf("The new prices are: %.2f\n", new_prices);
%Revenue
total_revenue = 0;
total_revenue = sum(prices.*last_week);
fprintf("Total Revenue is: %.f\n", total_revenue);
%average revenue
average_revenue = total_revenue/7;
fprintf("The average revenue is: %.f\n", average_revenue)
%cuts under 30
%cuts_under_30 = ;
% for cuts_under_30 = 1:numel(hairstyles)
% i = hairstyles(cuts_under_30);
% if new_prices < 30
% end
% disp(cuts_under_30)
fprintf("Cuts under 30 :\n")
fprintf('%.2f ', cuts_under_30);
fprintf('\n')

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Chunru
Chunru el 31 de Dic. de 2021
Editada: Chunru el 31 de Dic. de 2021
hairstyles = ["bouffant", "pixie", "dreadlocks", "crew", "bowl", "bob", "mohawk", "flattop"];
prices = [30, 25, 40, 20, 20, 35, 50, 35];
last_week = [2, 3, 5, 8, 4, 4, 6, 2];
total_price = sum(prices)
total_price = 255
average_price = mean(prices)
average_price = 31.8750
new_prices = prices()-5;
total_revenue = sum(prices.*last_week)
total_revenue = 1085
average_revenue = total_revenue/7
average_revenue = 155
cuts_under_30 = last_week(new_prices < 30) % the number of haircuts under $30
cuts_under_30 = 1×4
2 3 8 4
hairstyles (new_prices < 30) % the styles of haircuts under $30
ans = 1×4 string array
"bouffant" "pixie" "crew" "bowl"
new_prices(new_prices < 30)
ans = 1×4
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