double error syms code

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yogeshwari patel
yogeshwari patel on 4 Jan 2022
syms x t a
%a=1/2;
N=3;
U=zeros(1,2,'sym');
A=zeros(1,2,'sym');
B=zeros(1,2,'sym');
series(x,t)=sym(zeros(1,1));
U(1)=simplify(1+sin(x));
%alpha=input('enter the value of alpha=')
%case1
% for i=1:8
% U(i+1)=simplify((diff(U(i),x,2)+U(i))*gamma(a*(i-1)+1)/gamma((a*(i+1-1))+1));
% end
for i=1:3
A=0;
for j=1:i
A=A+U(j)*U(i-j+1);
end
U(i+1)=simplify((diff(U(i),x,2)-A(1))
end
disp(U)
for k=1:2
series(x,t)=simplify(series(x,t)+U(k)*(power(t,a*(k-1))));
end
series
% C=zeros(1,1);
% series
C=zeros(1,1);
for x=1:3
e=(x-1)/10;
for t=1:6
f=((t-1)/10);
C(x,t)=series(e,f);
end
end
The following error occurred converting from sym to double:
Unable to convert expression into double array.
Error in fractionakelingordanequation (line 33)
C(x,t)=series(e,f);
  1 Comment
Mitchell Thurston
Mitchell Thurston on 4 Jan 2022
it looks like this particular function is undefined at (0,0), so you might have some issues with that loop

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Accepted Answer

Steven Lord
Steven Lord on 4 Jan 2022
Preallocate C to be a sym array.
syms x
C=zeros(3, 6, 'sym')
C = 
C(2, 3) = x.^2
C = 

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