Adjacent Repeat of Numbers in an Array
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Olivia Rose
el 12 de Abr. de 2022
Comentada: Jacob
el 19 de Abr. de 2023
This is the current function
function adjacentRepeat = HasAdjacentRepeat(inArray)
for inArray=diff(inArray)
adjacentRepeat=1;
end
It works to satisfy the following requirements:
- Check for the use of a loop.
- Assessment result: correctCheck adjacentRepeat = 1 for inArray = [2 1 3 3 4 2 5].
- Assessment result: correctCheck adjacentRepeat = 1 for inArray = [4 5 7 6 3 8 9 7 2 8 9 7 3 3 3 7 1].
- Assessment result: correctCheck for correct adjacentRepeat for an array of randomized size and values.
But not for this requirement:
- Assessment result: incorrectCheck adjacentRepeat = 0 for inArray = [1 2 1 2 1].
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Image Analyst
el 12 de Abr. de 2022
You never set adjacentRepeat to 0, EVER. So of course it doesn't work.
Did you try just going through your difference array checking if any are 0? If they are, then the adjacent values are the same and you can set the variable and exit.
function adjacentRepeat = HasAdjacentRepeat(inArray)
adjacentRepeat = 0;
d = diff(inArray);
for k = 1 : length(d)
if d(k) == 0
adjacentRepeat = 1;
return;
end
end
end
2 comentarios
Jacob
el 19 de Abr. de 2023
I realized the problem I was having is I didnt understand what was or how to use diff. Thank you, this worked perfectly!
Más respuestas (1)
Image Analyst
el 12 de Abr. de 2022
Why do you have a for loop? Why not simply do this:
adjacentRepeat = HasAdjacentRepeat([2 1 3 3 4 2 5])
adjacentRepeat = HasAdjacentRepeat([4 5 7 6 3 8 9 7 2 8 9 7 3 3 3 7 1])
adjacentRepeat = HasAdjacentRepeat([1 2 1 2 1])
function adjacentRepeat = HasAdjacentRepeat(inArray)
adjacentRepeat = any(diff(inArray) == 0);
end
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