Arrayfun with multiple variable?

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MementoMori
MementoMori el 19 de Abr. de 2022
Editada: Stephen23 el 19 de Abr. de 2022
Hi, probably this question has already received answers but what I found don't solve my problem.
I know that I have a function that requires one input i can use arrayfun like this:
A=arrayfun(@functionExample, input1);
But if I have a function that requires more than one input how can I do?
Thanks

Respuestas (2)

Voss
Voss el 19 de Abr. de 2022
Two inputs:
A=arrayfun(@(x,y)functionExample(x,y), input1, input2);
Three inputs:
A=arrayfun(@(x,y,z)functionExample(x,y,z), input1, input2, input3);
And so on.
  3 comentarios
MementoMori
MementoMori el 19 de Abr. de 2022
Is this caused by varargin in the function "functionExample"
Stephen23
Stephen23 el 19 de Abr. de 2022
It is not required to use anonymous functions, a simple function handle works with any number of inputs:
V = arrayfun(@max,[1,2,3],[0,9,0])
V = 1×3
1 9 3

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Stephen23
Stephen23 el 19 de Abr. de 2022
Editada: Stephen23 el 19 de Abr. de 2022
"But if I have a function that requires more than one input how can I do?"
ARRAYFUN already works with any number of input arrays:
fnh = @(varargin)sum([varargin{:}]); % test function, any number of inputs
arrayfun(fnh,[1,2,3])
ans = 1×3
1 2 3
arrayfun(fnh,[1,2,3],[4,5,6])
ans = 1×3
5 7 9
arrayfun(fnh,[1,2,3],[4,5,6],[7,8,9])
ans = 1×3
12 15 18

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