Why are there negative PID coefficients?
67 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Maaz Madha
el 24 de Abr. de 2022
Comentada: Sam Chak
el 26 de Jun. de 2024
Hi all
The transfer function I have is a type 1 transfer function so it doens't respond to step response and has 0 steady state error. . (The transfer function).
However, when I use PID controller only negative gains can stabilise it and not positive, which is unusual and something which perplexes me. I would appreciate any insight as to why is that so and what that tells us about the system. Any help would be appreciated
0 comentarios
Respuesta aceptada
Sam Chak
el 24 de Abr. de 2022
Editada: Sam Chak
el 24 de Abr. de 2022
Hi @Maaz Madha
You have to look into the plant transfer function first. On the denominator, the 's' can be factored out. On the numerator, the last term is a 'minus' sign. Thus, the step response of the plant will go into the negative direction.
s = tf('s');
Gp = 13.11*(s + 37.85)*(s - 35.58)*(s + 0.03922)/(s*(s^2 + 0.06348*s + 0.1765)*(s^2 + 19.91*s + 148.7))
step(Gp, 1e3)
Gp =
13.11 s^3 + 30.27 s^2 - 1.765e04 s - 692.4
-------------------------------------------------
s^5 + 19.97 s^4 + 150.1 s^3 + 12.95 s^2 + 26.25 s
tem
To make the closed-loop system goes in the positive direction, naturally, the polarity of the proportional control gain has to be reversed. In this example, only the proportional controller is used to demonstrate the concept, Gc = -2.5827e-4.
Gc = -2.5827e-4;
Gcl = feedback(Gp*Gc, 1)
step(Gcl)
Gcl =
-0.003386 s^3 - 0.007819 s^2 + 4.56 s + 0.1788
----------------------------------------------------------
s^5 + 19.97 s^4 + 150.1 s^3 + 12.95 s^2 + 30.81 s + 0.1788
Applying the final value theorem, your can see that the step response of the closed-lopp control system will converge to , when . The direction of the system response is successful inverted. Note that PI and PID controllers are not needed to stabilize the plant.
2 comentarios
Muhammad Daffa Pratama
el 19 de Jun. de 2024
Hey I have the same problem but solved thanks to your explanation. But another problem arose. That negative proportional gain, when I check to its root locus, is in an unstable region. But my system is stable. How can that happen?
Sam Chak
el 26 de Jun. de 2024
Can you post a New Question on MATLAB Answers and provide the transfer function or state-space of the system?
Más respuestas (0)
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!