How to multiply 22x1 double with scalar?

Hi

I want to multiply like in the following code:

delta_x(i) = dx(i).*1.5;

type of dx is 22x1 double. 1.5 is scalar as you can see. When I do it like shown I get 22x1 double consisting of zeros. How do I have to multiply it, to get the right answer?

Thanks a lot

[Torsten]

If dx = 0 for all i, getting all zeros for delta_x is the right answer.

Answer 1

[Torsten]

If dx = 0 for all i, getting all zeros for delta_x is the right answer.

If you want to multiply delta_x by a scalar in a loop, use

delta_x(i ) = delta_x(i)*1.5;

[Bersin Tekmen]

Hi @Torsten dx is not Zero for all i. Thats the problem. The goal is, to use a 1.5x bigger dx for further operations. I wanted to call that "bigger" dx now delta_x... But when I do that operation, I get a Zero-Vector..

[Torsten]

One has to see the context - please include the relevant part of your code.

[Bersin Tekmen]

@Torsten thanks I solved the problem. I used the wrong counter variable.