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Grouping users into 3 groups using for loop and if statements

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Magsud Hasanov
Magsud Hasanov el 13 de Jun. de 2022
Comentada: Voss el 14 de Jun. de 2022
Hello, I am trying to group 75 different users into 3 groups by usage of electricity : Consumers, Prosumers and Producers. [ Prosumer = Consumption + Production].
The code I am writing is as follows:
load syncedData.mat %loading data - 3 tables (EdSynced, EgSynced and PSynced)
sum(EdSynced{:,2}) % this is how I get the demand (consumption) data
sum(EgSynced{:,2}) % this is how I get the generation data
% for pure consumers the EgSynced variable is full of zeros, so the sum is
% zero. And the same applies for pure producers vice versa.
class_code = zeros(75,3) % creating a matrix for further classification - 75 users and 3 groups
for i= 2:76 % in EdSynced and EgSynced these users are variables from 2 to 76 (75 various users)
for k=1:75 %
consume = sum(EdSynced{:,i});
generates = sum(EgSynced{:,i});
if consume > 0 && generates >0
class_code(k,1) = 1;
elseif consume ==0 && generates >0
class_code(k,2) = 1;
else
class_code(k,3) = 1;
end
end
end
After that I convert the matrix into table:
classes = ["Prosumer","Producer","Consumer"];
class_code = array2table(class_code,'VariableNames',classes)
But, unfortunately my code doesn't work properly. Could you please suggest a fix for it?
It outputs (the first segment of code) the matrix full of ones.
Thank you very much in advance!

Respuesta aceptada

Voss
Voss el 13 de Jun. de 2022
It seems like you should not be using two loops. That'll do the counting for every combination of i and k. Instead it seems like you want to do one loop (over i or k) where k=i-1.
class_code = zeros(75,3) % creating a matrix for further classification - 75 users and 3 groups
for ii = 2:76 % in EdSynced and EgSynced these users are variables from 2 to 76 (75 various users)
consume = sum(EdSynced{:,ii});
generates = sum(EgSynced{:,ii});
if consume > 0 && generates > 0
class_code(ii-1,1) = 1;
elseif consume == 0 && generates > 0
class_code(ii-1,2) = 1;
else
class_code(ii-1,3) = 1;
end
end
Of course, if that's how it should be, it can be done with zero loops.
  2 comentarios
Magsud Hasanov
Magsud Hasanov el 14 de Jun. de 2022
Thank you very much! The code that I used and it worked was something like this
class_code = zeros(75,3)
for k =1:75
consume = sum(Ed{:,k+1});
generates = sum(Eg{:,k+1});
if generates>0 && consume == 0
class_code(k,1) = 1;
elseif consume >0 && generates ==0
class_code(k,2) = 1;
else
class_code(k,3) = 1;
end
end
clear generates consume k
The idea is the same as yours, so I guess both give the same output.
Thank you very much!

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