How to populate a new vector by extracting only certain elements from another vector?

Hi everyone!
I would like to obtain two vectors new_vrx (with size 2xn) and new_vry (with size 2xn).
I would like to keep only those segments for which both the starting and ending point coordinates have values Vq1 = 0 and Vq2 = 0.
Vq1 = interp2(Xpix,Ypix,double(M),vrx(1,:),vry(1,:));
Vq2 = interp2(Xpix,Ypix,double(M),vrx(2,:),vry(2,:));
Could you help me? Thanks in advance

 Respuesta aceptada

Hi Loren,
if understood your question correctly, this should do what you want:
load('reticolo2D.mat');
[Xpix, Ypix] = meshgrid(1:321,1:241);
Vq1 = interp2(Xpix,Ypix,double(M),vrx(1,:),vry(1,:));
Vq2 = interp2(Xpix,Ypix,double(M),vrx(2,:),vry(2,:));
new_vrx = vrx(1,Vq1==0);
new_vry = vry(1,Vq1==0);
figure;plot(new_vrx,new_vry,'b-')
and
new_vrx = vrx(2,Vq2==0);
new_vry = vry(2,Vq2==0);
figure;plot(new_vrx,new_vry,'b-')
Best, Konrad

3 comentarios

@Konrad thanks but it doesn't answer my question. In the end I have to get just one plot, not two ones and I need a correspondence between new_vrx = vrx(1,Vq1==0) and new_vrx = vrx(2,Vq2==0); because they represent the x-coordinate of the initial and final point of the same segment. So if the x coordinate of the starting point exists, but the final one doesn't, I have to remove the whole segment anyway.
I don't understand what your data represents, but how about this:
load('reticolo2D.mat');
[Xpix, Ypix] = meshgrid(1:321,1:241);
Vq1 = interp2(Xpix,Ypix,double(M),vrx(1,:),vry(1,:));
Vq2 = interp2(Xpix,Ypix,double(M),vrx(2,:),vry(2,:));
new_vrx = vrx(:,Vq1==0&Vq2==0);
new_vry = vry(:,Vq1==0&Vq2==0);
figure;plot(new_vrx,new_vry,'b-')
"it doesn't answer my question." <== Well now you've accepted the answer so people will (rightfully?) assume that you have since figured it out.

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Creating and Concatenating Matrices en Centro de ayuda y File Exchange.

Productos

Preguntada:

el 15 de Jun. de 2022

Editada:

el 15 de Sept. de 2022

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by