How to apply moving harmonic average on an array?
4 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Nisar Ahmed
el 3 de Jul. de 2022
Hi,
I have attached the data Kd_i = (115*1), I want to keep first and last values as it is in the data (or also shown in the figure below) and in the row want compute the harmonic average of first and second values (red square), in the 3rd row I want to compute the harmonic average of second and thrid values (green square) asn so on...
I mean first and last values remain same (just to have final array/vector of equal length), and then from second row it moves the by computing the harmonic mean of first and second row, until second last row. Can someone help me to write it code?
Thanks
0 comentarios
Respuesta aceptada
Abhishek Tiwari
el 3 de Jul. de 2022
Hi,
A 'For' loop and harmmean() may do the same thing, as shown.
n = numel(Kd_i);
harmonicMean = Kd_i;
for idx = 2:n-1
harmonicMean(idx) = harmmean(Kd_i(idx-1 : idx, 1));
end
3 comentarios
Abhishek Tiwari
el 4 de Jul. de 2022
Yeah, harmonicMean has first and last values from Kd_i, and the remaining are the harmonic means of two rows (prev. and current).
Más respuestas (2)
Star Strider
el 3 de Jul. de 2022
If you want to calculate it as described in the harmmean More About section, perhaps something like this would work —
movhm = @(x) 2./movsum(1./x,2);
v = 1:5
movhm(v)
would work.
.
0 comentarios
dpb
el 3 de Jul. de 2022
Editada: dpb
el 4 de Jul. de 2022
Simplest is probably just brute-force --
HM=[Kd_1(1) arrayfun(@(i)harmmean(Kd_1(i:i+1)),1:numel(Kd_1)-1) Kd_1(end)].';
2 comentarios
dpb
el 4 de Jul. de 2022
Yeah, I made a local array of K=Kd_1(1:15) so wasn't too much to look at in command window...then didn't fix -- and arrayfun returns row vector didn't transpose...
Ver también
Categorías
Más información sobre Data Preprocessing en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!