Not sure how to do a smoothing average of noisy data
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Jason
el 19 de Feb. de 2015
Comentada: Jason
el 19 de Feb. de 2015
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/147206/image.jpeg)
Not sure how to do a smoothing average of noisy data based off what the instructions asked this is what I've come up with so far any help would be appreciated.
clear;
clc;
load('noisydata.mat','x');
N = x;
y = zeros(1,length(N));
for k = 2:1:length(x)
if (k~= 1 & k~= N)
y(k) = (x(k-1)+x(k+1))/2;
end
end
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Image Analyst
el 19 de Feb. de 2015
You forgot to set y(1) = x(1) before the loop, and, after the loop, set y(length(x)) = x(end). Then have your loop go from k = 2 : (length(x)-1).
3 comentarios
Image Analyst
el 19 de Feb. de 2015
Editada: Image Analyst
el 19 de Feb. de 2015
Well I said to put y(length(x))= x(end); after the loop, not inside it.
And for some reason you plotted only a single point
plot(y(k))
instead of the whole curve:
plot(x, 'r*-');
hold on;
plot(y, 'b-', 'LineWidth', 2);
But anyway, try that, because other than that it looks like it should work. But you didn't attach noisydata.mat so I can't test it.
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Geoff Hayes
el 19 de Feb. de 2015
Jason - I think that you have correctly interpreted what the question is asking (less the plot) but you may want to reconsider the condition for your if statement
if (k~= 1 & k~= N)
Remember that k is a scalar but N is a vector/array so this comparison is not what you want. If you want to exclude the first and last elements from x then just extend what you have started with the for statement
for k = 2:1:length(x)-1
So now k ranges from 2 to one less than the length of x which is exactly which values you need to consider (and so no longer have any need for the condition).
3 comentarios
Geoff Hayes
el 19 de Feb. de 2015
Jason - you are being asked to plot the original noisy data versus the sample number. The sample numbers are the indices into your noisy matrix x. How would you plot this?
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