Plotting a 3d gaussian function using surf
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Desmond Johnson
el 27 de Feb. de 2015
Comentada: Xiang Chen
el 16 de Oct. de 2018
Let me start off by saying that I am extremely new to MATLAB. I would to use these functions and turn them into a 3d plot using surf. I have already made a mesh grid of my x and y but I am confused on how to plug my gaussian function in as Z. I would like the surf plot to look like this http://i.stack.imgur.com/QiTPe.png
x=randn(1,10000);
y=x';
[X,Y]=meshgrid(x,y);
z=(1000/sqrt(2*pi)*exp(-X.^2/2))
surf(x,y,z);shading interp
Thanks in advance for the help.
1 comentario
Xiang Chen
el 16 de Oct. de 2018
This is garbage answer. Making the matrix smaller will be much better.
Respuesta aceptada
Star Strider
el 27 de Feb. de 2015
Editada: Star Strider
el 27 de Feb. de 2015
This works:
N = 3.0;
x=linspace(-N, N);
y=x;
[X,Y]=meshgrid(x,y);
z=(1000/sqrt(2*pi).*exp(-(X.^2/2)-(Y.^2/2)));
surf(X,Y,z);
shading interp
axis tight
Experiment to get the result you want.
5 comentarios
Star Strider
el 28 de Feb. de 2015
My pleasure.
You have to use a linear vector in x and y, as did I with linspace. I see no reason to use randn here, since it is by definition random and will create very strange matrices with meshgrid.
To experiment, do a simple surf plot of the meshgrid outputs using a randn vector and using linspace for x and y. Use different randn calls for x and y each in order to avoid the ‘banding’ you saw in the plot you posted.
If you want to use randn at all to look at the distribution of the points, consider using scatter3:
x = randn(1,10000);
y = randn(1,10000);
zf=@(X,Y) (1000/sqrt(2*pi).*exp(-(X.^2/2)-(Y.^2/2)));
z = zf(x,y);
figure(1)
scatter3(x, y, z, 'b.')
grid on
Rotate it in the GUI to get an interesting perspective on the density of the distribution.
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