How to transform the normalized values of a histogram (i.e. the bars heights) in percentages?

How to transform the normalized values of this histogram (i.e. the bars heights) in percentages?

I should multiply the bars values by 100, but how to do it ? (maybe inside the "histogram" function)

a = [0 0 0 1 1 1 1 1 1 3 3 3  2 2 4 4 39 39 39 39 39 39 40 40 40 40 40 40 40 0 0 0 0 0 0 0 41 41 41];
histogram(a,'Normalization','probability')

This could be a workaround:

bar(histcounts(a)/(sum(histcounts(a)))*100)

BUT:

1. the bars are shifted towards right (why??)
2. I would like to still use the "histogram" function (if possible, obviously)

Any idea ?

[Les Beckham]

To fix the "shifted towards right" issue, use this

a = [0 0 0 1 1 1 1 1 1 3 3 3  2 2 4 4 39 39 39 39 39 39 40 40 40 40 40 40 40 0 0 0 0 0 0 0 41 41 41];
bar(0:(numel(histcounts(a))-1), histcounts(a)/(sum(histcounts(a)))*100)
grid on

bar(y) is equivalent to bar(1:numel(y), y), hence the "shift".

[Sim]

Oh cool, thanks a lot @Les Beckham!! :-)

[Les Beckham]

You are quite welcome.

Answer 1

[Star Strider]

Altering the histogram plot is likely not possible because the ‘Values’ vector is read-only.

The easiest approach is likely to re-plot the bar plot using the derived values —

a = [0 0 0 1 1 1 1 1 1 3 3 3  2 2 4 4 39 39 39 39 39 39 40 40 40 40 40 40 40 0 0 0 0 0 0 0 41 41 41];

figure
hh = histogram(a,'Normalization','probability');
xlabel('Centers')
ylabel('Probability')

Values = hh.Values*100;
Cntrs = hh.BinEdges(1:end-1) + diff(hh.BinEdges)/2;

figure
bar(Cntrs, Values)
xlabel('Centers')
ylabel('Percent')

.

[Sim]

Thanks a lot @Star Strider for your explanation and solution! .....To some extent, it looks like that your solution is kind of similar to that one of @Les Beckham (if I am not wrong) :-) ......Many many thanks!!!

[Star Strider]

As always, my pleasure!

The histcounts function is an option, however you mentioned that you wanted to use the histogram function, so I went with that.

[Sim]

@Star Strider Yes yes, true, many thanks for having presented a solution related to the histogram function, I am very grateful! (this is a way to learn/understand deeper the functions available in Matlab)

[Star Strider]

As always, my pleasure!