Precision of num2str function

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Panagiotis Artemiou
Panagiotis Artemiou el 5 de Abr. de 2023
Comentada: Panagiotis Artemiou el 9 de Abr. de 2023
I try to make o PRNG using the middle square method.
When I come the the point where I need to keep the middle digits of a number. I convert from double to string.
The precision is set in the function as 8. But after 70 iterations it does not have the the desired precision when converting from double to string.
The code can be seen bellow.
format long
seed=2315;
m=256;
z(1)=seed;
for i=2:m
z(i-1)=z(i-1)^2;
u(i-1)=z(i-1)/(10^(2*4));
t=convertStringsToChars(num2str(u(i-1),8));
temp=t(5:8);
temp=str2double(temp);
z(i)=temp;
end
For example when i=69 u(i-1)=0.06270016 and when it converts to string and then char it becomes '0.06270016'
And when i=70 u(i-1)=0.07290000 but this becomes '0.0729'.
How can I make it be '0.07290000' after the conversion?

Respuesta aceptada

Stephen23
Stephen23 el 5 de Abr. de 2023
Editada: Stephen23 el 5 de Abr. de 2023
If you want that much control over the text format then you should be using SPRINTF.
But in lieu of that, you can specify the format string with NUM2STR:
num2str(0.06270016,'%.8f')
ans = '0.06270016'
num2str(0.0729,'%.8f')
ans = '0.07290000'
  1 comentario
Panagiotis Artemiou
Panagiotis Artemiou el 9 de Abr. de 2023
Thank you very much. This was really helpful!

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