Convertion from U16 in U8 results overflow. Why?
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Hello all,
I made the following example:
typedef unsigned int U16;
typedef unsigned char U8;
// case 1;
U16 a = 0x0FFF;
U16 b = 0x0E00;
U8 c = 0x00;
//case 2:
U16 d = 0xFFFF;
U16 e = 0x0011;
U16 f = 0;
void main()
{ //case 1:
c = (U8) (a-b); // -> red check overflow
//case 2:
f = (U8) ((d + e)&0x00FF); // + red warning -> no effect of 0x00FF
}
When I run the Polyspace (Code Prover R2014b) analysis, I receive the following red checks:
1) Error: operation [conversion from unsigned int16 to unsigned int8] on scalar overflows (result is always strictly greater than MAX UINT8) conversion from unsigned int 16 to unsigned int 8
2) Error: operation [+] on scalar overflows (result is always strictly greater than MAX UINT16) operator + on type unsigned int 16
If I change the code from:
c = (U8) (a-b);
to
c = (U8) ((a-b)&0x00FF);
I don't receive the first red warning. Which is the correct configuration for overflow for no error occurring?
1 comentario
Titus Edelhofer
el 22 de Abr. de 2015
Hi Christina,
is your question answered with the answers of Alex and myself?
Titus
Respuesta aceptada
Más respuestas (1)
Titus Edelhofer
el 10 de Abr. de 2015
Editada: Titus Edelhofer
el 10 de Abr. de 2015
Hi,
hmm, I guess the first error is explainable: you indeed have an overflow here.
hex2dec('0FFF')-hex2dec('0E00')
ans =
511
which is larger than 255. This overflows when cast to U8.
The second error is also correct: your plus operation overflows in U16. Doing the "&" afterwards does not help here, because the error occurred inside the (d+e).
last but not least:
c = (U8) ((a-b)&0x00FF);
does not error, because (a-b) is fine (it's done in U16 and a>b). The "&" "removes" the bits larger than 255. Then casting to U8 is safe.
Titus
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