Find the inear indices of a specific value in a 3d matrix using the positions of a 2d matrix

If I have one 3d matrix A, and one 2d matrix B, how can I find the linear indices of a specific value of A in all its pages, given the position of another value of B?

For instance, if A is a 3x4x4 matrix like:

    A(:,:,1)=

     0 1 2 0
     1 1 0 2
     2 2 0 1

    A(:,:,2)=

     2 0 0 0
     0 1 0 2
     2 0 1 1

and B is a 3x4 one:

    1 1 1 1
    2 2 2 2
    3 3 3 3

I would like to find all the linear indices of A == 2 when B == 1, such as:

    LinInd= [7; 13]

How can I do that?

Answer 1

[Guillaume]

Hum, that is a bit tricky indeed. One possible way to solve it would be to repmat the second conditions across the pages of A:

find(A == 2 & repmat(B == 1, [1 1 size(A, 3)]))

edit: Not sure where you get your [7;10] result. I get [7;13]

[Umberto Minora]

I edited my question. Indeed, it was [7;13], I was wron in counting the positions. Thanks a lot, it worked!

Answer 2

[James Tursa]

Another way:

find(bsxfun(@and,A==2,B==1))