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The code is plotting $R_0$ against two parameters

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Codex
Codex el 30 de Oct. de 2023
Editada: Dyuman Joshi el 24 de Nov. de 2023
I have been trying to run this code but it give me this error:
Error in Testing_1 (line 21)
[c,h] = contourf(alpha_3,alpha_1,R_0',levels);
%Basic Reproduction Number
alpha_m = 1/8.5; %Rate at which exposed men respectively become infectious
alpha_f = 1/22; %Rate at which exposed women respectively become infectious
tau_m = 1/8.5; %Rate at which infectious men respectively recover
tau_f = 1/21; %Rate at which infectious women respectively recover
beta_mm = 0.23; %Transmission probability from infectious men having sex with susceptible men
beta_ff = 0.18; %Transmission probability from infectious women having sex with susceptible women
beta_mf = 0.01; %Transmission probability from infectious men having sex with susceptible women
beta_fm = 0.18; %Transmission probability from infectious women having sex with susceptible men
alpha_1 = 0.01; %Modification parameters in reducing transmission
alpha_2 = 0.1; %Modification parameters in reducing transmission
alpha_3 = 1.5; %Modification parameters in reducing transmission
I_f = 27; %Population of infectious women
I_m = 28.22; %Population of infectious men
R_0 = (alpha_3 * beta_ff * tau_m + beta_mm * tau_f)/(2 * tau_f * tau_m) + sqrt(4*alpha_1*alpha_2*beta_fm*beta_mf*tau_f*tau_m + alpha_3^2*beta_ff^2*tau_m^2 - 2*alpha_3 * beta_ff * beta_mm * tau_f * tau_m + beta_mm^2 * tau_f^2)/(2 * tau_f * tau_m);
% plot
levels = (0:0.2:1.2);
[c,h] = contourf(alpha_3,alpha_1,R_0',levels);
Error using contourf
Z must be at least a 2x2 matrix.
clabel(c,h)
h.LineWidth = 2; % contour line width (up to you)
xlabel('\alpha_3');
ylabel('\alpha_1');
colormap(jet(numel(levels)-1));
colorbar('vert');
I will appreciate a response.
  7 comentarios
Codex
Codex el 30 de Oct. de 2023
R_0 represent basic reproduction number.
alpha_1 = 0.01; %Modification parameters in reducing transmission
alpha_3 = 1.5; %Modification parameters in reducing transmission
This is to investigate the relation of the basic reproduction number (R_0) against the alpha_1 and alpha_3. And it can be R_0 against beta_mm
Dyuman Joshi
Dyuman Joshi el 24 de Nov. de 2023
Editada: Dyuman Joshi el 24 de Nov. de 2023
It's not possible to draw a surface plot with scalar data.
You can see that in the answer below, Walter has defined alpha_1 and alpha_3 as grids, only then a surface plot is obtained.
Are you using a research paper as reference and trying to reproduce some results? If so, then please share additional information regarding it.

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Respuestas (1)

Walter Roberson
Walter Roberson el 30 de Oct. de 2023
I had to guess about the range of alpha_1 and alpha_3 that you wanted to plot.
The contour turns out solid color because the values of R_0 are mostly more than max(levels)
The surface is pretty boring except for a small area near the origin. And if you go too far from the origin then there is a part where the surface goes complex valued. So you would need to tell us what plot range to look at.
%Basic Reproduction Number
alpha_m = 1/8.5; %Rate at which exposed men respectively become infectious
alpha_f = 1/22; %Rate at which exposed women respectively become infectious
tau_m = 1/8.5; %Rate at which infectious men respectively recover
tau_f = 1/21; %Rate at which infectious women respectively recover
beta_mm = 0.23; %Transmission probability from infectious men having sex with susceptible men
beta_ff = 0.18; %Transmission probability from infectious women having sex with susceptible women
beta_mf = 0.01; %Transmission probability from infectious men having sex with susceptible women
beta_fm = 0.18; %Transmission probability from infectious women having sex with susceptible men
%alpha_1 = 0.01; %Modification parameters in reducing transmission
alpha_2 = 0.1; %Modification parameters in reducing transmission
%alpha_3 = 1.5; %Modification parameters in reducing transmission
I_f = 27; %Population of infectious women
I_m = 28.22; %Population of infectious men
% plot
levels = (0:0.2:1.2);
[alpha_1, alpha_3] = meshgrid(0:0.005:0.03, 1:0.05:2);
R_0 = (alpha_3 .* beta_ff .* tau_m + beta_mm .* tau_f)./(2 .* tau_f .* tau_m) + sqrt(4 .* alpha_1 .* alpha_2 .* beta_fm .* beta_mf .* tau_f .* tau_m + alpha_3.^2 .* beta_ff.^2 .* tau_m.^2 - 2 .* alpha_3 .* beta_ff .* beta_mm .* tau_f .* tau_m + beta_mm.^2 .* tau_f.^2) ./ (2 .* tau_f .* tau_m);
Name Size Bytes Class Attributes I_f 1x1 8 double I_m 1x1 8 double R_0 21x7 1176 double alpha_1 21x7 1176 double alpha_2 1x1 8 double alpha_3 21x7 1176 double alpha_f 1x1 8 double alpha_m 1x1 8 double beta_ff 1x1 8 double beta_fm 1x1 8 double beta_mf 1x1 8 double beta_mm 1x1 8 double cmdout 1x33 66 char levels 1x7 56 double tau_f 1x1 8 double tau_m 1x1 8 double
[c,h] = contourf(alpha_3,alpha_1,R_0,levels);
clabel(c,h)
h.LineWidth = 2; % contour line width (up to you)
xlabel('\alpha_3');
ylabel('\alpha_1');
colormap(jet(numel(levels)-1));
colorbar('vert');
figure()
surf(alpha_3,alpha_1,R_0);
view(3)

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