NaN error fills up my zeros array despite the hand calcs checking out.

I am trying to plot the nondimensionalized time-dependent temperture distribution. The function checks out and the code works, except that my zeros array is being filled with NaN. I am not sure where the issue lies because the hand calculations return values.
Here is the code:
close all
clear all
clc
x_til = [0 : 0.2 : 1];
dt = 0.01;
tmax = 1;
t_til = [dt : dt : tmax];
nx = length(x_til);
nt = length(t_til);
gamma = 0.1;
TX10Bexp0 = zeros(nx,nt);
for ix = 1:nx
for it = 1:nt
TX10Bexp0(ix,it) = fX10Bexpo0T0(x_til(ix),t_til(it),gamma);
end
end
figure
clf;
hold on
for ix = 1:nx
plot(t_til, TX10Bexp0(ix,:), 'LineWidth',3);
end
xlabel('dimensionless time')
ylabel('dimensionless temperature')
And here is the function:
function [T_til] = fX10Bexpo0T0 (x_til, t_til, gamma)
A = 6;
MAX = 1000;
mmax = ceil(sqrt(A*log(10)/t_til)/pi + 0.5);
if mmax > MAX
mmax = MAX;
end
sum = 0;
sum2 = 0;
for m=1:mmax
lambda = (2*(m-1))*pi/2;
sum = sum + sin(lambda*x_til)/lambda*exp(-(lambda^2)*t_til);
sum2 = sum2 + sin(lambda*x_til)/lambda/(lambda^2-gamma)*(exp(-(lambda^2)*t_til)-exp(-gamma*t_til));
end
T_til = exp(-gamma*t_til) - (2*sum) - (2*gamma*sum2);
end

1 comentario

KALYAN ACHARJYA
KALYAN ACHARJYA el 14 de Nov. de 2023
Editada: KALYAN ACHARJYA el 14 de Nov. de 2023
Please verify, as TX10Bexp0(ix, it) reflects only NaN values

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Respuestas (1)

Jon
Jon el 14 de Nov. de 2023
Editada: Jon el 14 de Nov. de 2023
The term lambda in the denominator of the expression for sum2 is zero when m = 1, so sum2 will be NaN and so will T_til
x_til = 0.1
x_til = 0.1000
t_til = 0.1
t_til = 0.1000
sum2 = 0
sum2 = 0
gamma = 0.1
gamma = 0.1000
m = 1
m = 1
lambda = (2*(m-1))*pi/2
lambda = 0
sum2 = sum2 + sin(lambda*x_til)/lambda/(lambda^2-gamma)*(exp(-(lambda^2)*t_til)-exp(-gamma*t_til))
sum2 = NaN

1 comentario

Also, note that gamma is the gamma function in MATLAB, so you may want to use a different variable name to avoid confusion

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R2023b

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Preguntada:

el 14 de Nov. de 2023

Comentada:

Jon
el 14 de Nov. de 2023

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