How do I change this system with function handles to linear equations to plot discretely?
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balla243
el 4 de Feb. de 2024
Comentada: Walter Roberson
el 4 de Feb. de 2024
Hi, I don't know how to implement a unit function and still plot discretely. Also, I don't really understand what the "double" does in my code but somehow I need it. Please advise - TIA.
u = @(n) double(n>=0); %converts symbolic u to array of n
uu = @(n) 1*(n>=0); %unit step function
x = @(n) u(n-2)-u(n-4);
n=[-2,12];
h = @(n) uu(n).*(sin(n).*exp(-n));
fplot(x,[-2,12]); %plots within x-limits
hold on
fplot(h,[-2,12]);
grid on
y = @(n) x(n).*h(n);
fplot(y,[-2,12]);
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Respuesta aceptada
Walter Roberson
el 4 de Feb. de 2024
Movida: Walter Roberson
el 4 de Feb. de 2024
u = @(n) double(n>=0); %converts symbolic u to array of n
uu = @(n) 1*(n>=0); %unit step function
x = @(n) u(n-2)-u(n-4);
n=[-2,12];
h = @(n) uu(n).*(sin(n).*exp(-n));
T = linspace(-2,12);
stem(T, x(T)); %plots within x-limits
hold on
stem(T, h(T));
grid on
y = @(n) x(n).*h(n);
stem(T, y(T));
ylim([-.1 1.1])
2 comentarios
Walter Roberson
el 4 de Feb. de 2024
The double() is not needed.
fplot() plots against the given range automatically, chosing plotting points according to how bumpy the function is. It does not plot discretely.
stem() plots discretely, but it needs to be told which points to plot.
u = @(n) (n>=0); %converts symbolic u to array of n
uu = @(n) 1*(n>=0); %unit step function
x = @(n) u(n-2)-u(n-4);
n=[-2,12];
h = @(n) uu(n).*(sin(n).*exp(-n));
T = linspace(-2,12);
stem(T, x(T)); %plots within x-limits
hold on
stem(T, h(T));
grid on
y = @(n) x(n).*h(n);
stem(T, y(T));
ylim([-.1 1.1])
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