How can I extract the position of the correlation peak between every two consecutive frame and plot its time varying position?

14 visualizaciones (últimos 30 días)
Parastoo
Parastoo el 7 de Mzo. de 2024
Respondida: Sudarsanan A K el 19 de Mzo. de 2024
Hello friends,
I have a series of consecutive binary frames. I want to extract the position of the correlation peak between every two consecutive frame and plot its time varying position, with the amplitude denoting the shift in the position of the correlation peak in pixel units of the camera.
Could you possibly help me to reach my solution? any help you might be able to give me would be greately appreciated.

Iniciar sesión para responder a esta pregunta.

Respuestas (1)

Sudarsanan A K
Sudarsanan A K el 19 de Mzo. de 2024
Ran in:
Hi Parastoo,
To extract the position of the correlation peak between consecutive binary frames, you can use the "normxcorr2" and "max" functions in MATLAB. Here is a step-by-step approach:
  1. Load your binary frames: Ensure your frames are in a format that MATLAB can easily access, such as a series of matrices or a multi-dimensional array where each page is a frame.
  2. Perform cross-correlation between consecutive frames: For each pair of consecutive frames, you will use the cross-correlation function to determine the shift. MATLAB's "xcorr2" function is suitable for 2D data like images.
  3. Compute the peak of the cross-correlation between consecutive frames: The peak position indicates the shift between frames. You will need to find the indices of this peak using the "max" function.
  4. Plot the time-varying position of the correlation peaks: Finally, plot the shift in positions (row shift and column shift) of the correlation peaks over time. The amplitude will denote the shift in pixel units.
Here is an example demonstration with synthetic binary frames:
%% Generate synthetic binary frames (example for a linear diagonal motion from top-left to bottom-right)
% Parameters
numFrames = 16; % Number of frames
frameSize = [20, 20]; % Size of each frame
objectSize = 4; % Size of the moving object
motionStep = 1; % Object motion step in pixels per frame
% Initialize frames
frames = false(frameSize(1), frameSize(2), numFrames);
% Generate frames with a moving object
for i = 1:numFrames
objectPosition = 1 + (i-1) * motionStep;
frames(objectPosition:(objectPosition+objectSize-1), objectPosition:(objectPosition+objectSize-1), i) = true;
end
frames
frames = 20×20×16 logical array
frames(:,:,1) = 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 frames(:,:,2) = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 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0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 frames(:,:,6) = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 frames(:,:,7) = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 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%% Compute cross-correlation between consecutive frames
% Initialize array to hold peak positions
peakPositions = zeros(numFrames-1, 2); % Each row will hold [rowShift, colShift]
for i = 1:numFrames-1
% Cross-correlation
corr = xcorr2(frames(:,:,i), frames(:,:,i+1));
% Find the peak
[~, maxIndex] = max(corr(:));
[peakRow, peakCol] = ind2sub(size(corr), maxIndex);
% Adjust for the fact that the peak of the auto-correlation (zero shift) is in the center of the matrix
center = size(corr) / 2;
peakPositions(i, :) = round([peakRow, peakCol] - center);
end
%% Plot the time-varying position of the correlation peaks
% Time vector
timeVector = 1:numFrames-1;
% Plot
figure;
plot(timeVector, peakPositions(:,1), 'b-o', 'DisplayName', 'Row Shift');
hold on;
plot(timeVector, peakPositions(:,2), 'm-x', 'DisplayName', 'Column Shift');
xlabel('Frame');
ylabel('Shift (pixels)');
title('Time-Varying Position of Correlation Peaks');
legend show;
In this example, the resulting figure reflects the linear diagonal movement of the object from top-left to bottom-right of the frame, by indicating the constant shift (pixels) across the frames.
For more information about the functions used in this example, refer to the following documentations:
I hope this helps!

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