how can i divide an image into 2 equal parts.horizontaly,?
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sara
el 20 de Abr. de 2015
Respondida: vahid rowghanian
el 4 de Abr. de 2021
this code works for 3 equal horizontal parts,how can i change it for 2 parts?
if true
[n,m]=size(im) % im is your image
id=fix(n/3)
im1=im(1:id,:);
im2=im(id+1:2*id,:);
im3=im(2*id+1:n,:);
end
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Image Analyst
el 20 de Abr. de 2015
You can use imcrop, which will work for color and gray scale images:
[rows, columns, numberOfColorChannels] = size(im);
topHalf = imcrop(im, [1, 1, columns, floor(rows/2)]);
bottomHalf = imcrop(im, [1, ceil(rows/2), columns, floor(rows/2)]);
Or if you know for a fact that it's a 2D monochrome image
[rows, columns, numberOfColorChannels] = size(im);
middleRow = floor(rows/2);
topHalf = im(1:middleRow, :);
bottomHalf = im(1+middleRow:end, :);
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vahid rowghanian
el 4 de Abr. de 2021
If you want to divide the image into squares of size gs ( e.g. 2,3,4,5,6,7,8,9,10,…), you can use the following code. This function extracts gs by gs patches from the input image and stores them into 'patch' variable. Notice that, if width or height of the input image is not a multiple of gs, then an offset equal to residual of the division won't be covered in patch extraction.
function [ patchim , npatchim ] = divideimage (im , gs)
imheight=size(im,1);
imwidth=size(im,2);
maxgsrow = floor( imheight / gs);
maxgscol = floor( imwidth / gs );
npatch = 1;
for i = 1 : maxgsrow
for j = 1 : maxgscol
rmin = ( i - 1 ) * gs + 1;
rmax = i * gs;
cmin = ( j - 1) * gs + 1;
cmax = j * gs;
%%%%% do processes
patch ( : , : , : , npatch) = im( rmin : rmax , cmin : cmax , : );
npatch = npatch + 1;
endfor
endfor
npatchim = npatch - 1;
patchim = patch;
end
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